如何编写 SQL 查询以水平显示值 [英] How to write a SQL query to present values horizontally

问题描述

假设我有一张名为 Jobs 的表:

Suppose I have one table called Jobs:

CREATE TABLE [Jobs]
(
    [JOBID] [int] IDENTITY(1,1) NOT NULL,
    [PARTDESC] [nvarchar](64) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [OrderPlacedBy] [nvarchar](64) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
    [SpecialistName] [nvarchar](64) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [Priority] [int] NOT NULL,
    [Symptoms] [ntext] COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [CustomerNotes] [ntext] COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [ShopNotes] [ntext] COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [JobType] [nvarchar](32) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [JobState] [nvarchar](32) COLLATE Latin1_General_CI_AS NULL,
    [JobAddedDate] [datetime] NOT NULL,
    [JobStartedDate] [datetime] NULL,
    [JobFinishedDate] [datetime] NULL,
    [JobShippedDate] [datetime] NULL,
    [RecievedDate] [datetime] NULL
)

我想横向查看专家姓名和他的工作 ID.

I want to see the specialist name and his jobs IDs horizontally.

ANA 201,502,605,701,774
BEN 102,103,051
JEN 705,401,402,509,409,408

专家可能有 n 个工作.假设专家 ANA 有 10 个工作，而 BEN 有 5 个工作.

A specialist may have n jobs. Suppose specialist ANA has 10 jobs where BEN has 5 jobs.

通过这种方式，我想横向向专家展示他的工作，其中每个专家的工作数量可能会有所不同.

In this way I want to show specialist his jobs horizontally where the number of jobs may vary per specialist.

如何在 SQL 中执行此操作?

How can I do this in SQL?

推荐答案

Marc 是对的.不要在 SQL 中执行此操作，而应在表示级别执行此操作.不过，如果你想这样做，看看这里:如何从 sql 中具有动态内容的 2 个不同表中返回 1 个单行数据

Marc is right. Don't do this in SQL, do it at the presentation level. Still, if you want to do this, take a look here: How to return 1 single row data from 2 different tables with dynamic contents in sql

适用于您的情况，代码可能是:

Applied to your situation, the code might be:

     select SpecialistName , LEFT(JobsIds, len(JobsIds)-1) as JobsIds from 
(SELECT j.SpecialistName ,

      ( SELECT cast(j1.JobsId as varchar(10)) + ','

           FROM Jobs j1

          WHERE j1.SpecialistName = j.SpecialistName

          ORDER BY JobId

            FOR XML PATH('') ) AS JobsIds
      FROM Jobs j
      GROUP BY SpecialistName )A;

这篇关于如何编写 SQL 查询以水平显示值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！