如何将 XML 列连接回它源自的记录? [英] How can I join an XML column back onto the record it originates from?

问题描述

我在 SQL Server 2005 的数据库中有一个表Blah"，其中包含一个 PK 列 BlahID 和一个 XML 列 BlahItems.

该表有如下记录...

<前>BlahID BlahItems------ ------------------------------------------------------1 <root><item name="Fred"/><item name="Wilma"/></root>2 <root><item name="Lisa"/><item name="Bart"/></root>

如何查询该表以生成以下内容....

<前>BlahID BlahItem------ ------1 弗雷德1 威尔玛2 丽莎2 巴特

我设法获得的最接近的是每条记录的功能，它按照以下方式执行某些操作...

CREATE FUNCTION dbo.Blahs(@id int)返回 @list 表 (BlahID int, BlahItem nvarchar(max))开始声明 @xml 为 xmlSELECT @xml = BlahItems FROM dbo.Blah AS b WHERE b.BlahID = @id插入@listSELECT @id, tbl.col.value('@name','nvarchar(max)')FROM @xml.nodes('/root/item') tbl(col)返回结尾SELECT * FROM dbo.Blahs(1)

<前>BlahID BlahItem------ ------1 弗雷德1 威尔玛

我的最终目标是创建扩展"数据的 VIEW，然后针对该视图进行查询.

解决方案

你可以试试这个查询:

SELECT BlahID, XmlItems.BlahItem.value('@name', 'nvarchar(100)') AS BlahItemFROM Blah CROSS APPLY BlahItems.nodes('/root/item') AS XmlItems(BlahItem)

有关详细信息，请查看 Alex Homer 的这篇由三部分组成的文章.

I have a table "Blah" with a PK column BlahID and an XML column BlahItems in a database on SQL Server 2005.

This table has records as follows...

BlahID BlahItems
------ ------------------------------------------------------
1      <root><item name="Fred" /><item name="Wilma" /></root>
2      <root><item name="Lisa" /><item name="Bart" /></root>

How can I query that table to produce the following....

BlahID BlahItem
------ --------
1      Fred
1      Wilma
2      Lisa
2      Bart

The closest I've managed to get is on a per record FUNCTION that does something along the lines of the following...

CREATE FUNCTION dbo.Blahs(@id int)
RETURNS @list TABLE (BlahID int, BlahItem nvarchar(max))
BEGIN
    DECLARE @xml AS xml
    SELECT @xml = BlahItems FROM dbo.Blah AS b WHERE b.BlahID = @id

    INSERT INTO @list
    SELECT @id, tbl.col.value('@name','nvarchar(max)')
    FROM @xml.nodes('/root/item') tbl(col)
    RETURN
END

SELECT * FROM dbo.Blahs(1)

BlahID BlahItem
------ --------
1      Fred
1      Wilma

My ultimate goal is to create a VIEW of the "expanded" data and then query against the view.

解决方案

You can try this query:

SELECT BlahID, XmlItems.BlahItem.value('@name', 'nvarchar(100)') AS BlahItem
FROM Blah CROSS APPLY BlahItems.nodes('/root/item') AS XmlItems(BlahItem)

For more info check this three-part article by Alex Homer.

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