如何在sql server 2005中拆分时间并计算时差? [英] How to Split Time and calculate time difference in sql server 2005?

问题描述

我想用sql server 2005分割时间并计算时差

i want to split the time and calculate time difference using sql server 2005

我的默认输出是这样的:

my default output is like this:

EnrollNo     AttDateFirst                          AttDateLast
111      2011-12-09 08:46:00.000          2011-12-09 08:46:00.000
112      2011-12-09 08:40:00.000          2011-12-09 17:30:00.000
302      2011-12-09 09:00:00.000          2011-12-09 18:30:00.000
303      2011-12-09 10:00:00.000          2011-12-09 18:35:00.000

我希望我的新输出是这样的:

I want my new output to be like this:

Enroll No     .....      FirtTime       LastTime      Time Diff
111           .....      8:46:00          8:45:00     00:00:00
112           .....      8:30:00         17:30:00      9:00:00
302           .....      9:00:00         18:30:00      9:30:00 
303           .....     10:00:00         18:35:00      8:35:00

推荐答案

您可以使用此查询:

select EnrollNo, convert(varchar, AttDateFirst, 8) as FirstTime,
                 convert(varchar, AttDateLast, 8) as LastTime,
                 convert(varchar, AttDateLast - AttDateFirst, 8) as [Time Diff]
from YourTable

返回以下结果:

EnrollNo    FirstTime                      LastTime                       Time Diff
----------- ------------------------------ ------------------------------ ------------------------------
111         08:46:00                       08:46:00                       00:00:00
112         08:30:00                       17:30:00                       09:00:00
302         09:00:00                       18:30:00                       09:30:00
303         10:00:00                       18:35:00                       08:35:00

这篇关于如何在sql server 2005中拆分时间并计算时差?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！