跳过后续行中相同值的输出 [英] Skipping the output of identical values in subsequent rows
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问题描述
朋友
我想使用 tbale tblABC 中的 sql 查询来跟踪输出类型
I want following type of output with sql query from tbale tblABC
OUTPUT
======
SrNo. Date BillNo Amount
=================================================
1 10-02-2012 VAT-1 1200.00
2 RET-4 50.00
3 RET-5 150.50
4 11-02-2012 VAT-2 1500.00
5 RET-6 2505.00
6 12-02-2012 VAT-3 05.00
来自具有以下数据的表
tblABC
======
SrNo. Date BillNo Amount
=================================================
1 10-02-2012 VAT-1 1200.00
2 10-02-2012 RET-4 50.00
3 10-02-2012 RET-5 150.50
4 11-02-2012 VAT-2 1500.00
5 11-02-2012 RET-6 2505.00
6 12-02-2012 VAT-3 05.00
我想要的 OUTPUT 和 table 之间的区别在于输出我不想要日期重复,因为它在表格中.
The diffrence between the OUTPUT i want and table is that in OUTPUT i don't want Date Reptetion as it is in table.
请帮助我如何拥有它.
推荐答案
DECLARE @tblABC TABLE
(
SrNo INT, [Date] DATETIME, BillNo CHAR(5), Amount DECIMAL(10,2)
);
INSERT @tblABC SELECT 1,'20120210','VAT-1',1200.00
UNION ALL SELECT 2,'20120210','RET-4',50.00
UNION ALL SELECT 3,'20120210','RET-5',150.50
UNION ALL SELECT 4,'20120211','VAT-2',1500.00
UNION ALL SELECT 5,'20120211','RET-6',2505.00
UNION ALL SELECT 6,'20120212','VAT-3',05.00;
;WITH x AS
(
SELECT SrNo, [Date] = REPLACE(CONVERT(CHAR(10), [Date], 103), '/', '-'),
BillNo, Amount, rn = ROW_NUMBER() OVER (PARTITION BY [Date] ORDER BY SrNo)
FROM @tblAbC
)
SELECT SrNo, [Date] = CASE rn WHEN 1 THEN [Date] ELSE '' END, BillNo, Amount
FROM x
ORDER BY SrNo;
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