std::list 是否保证项目永远不会被移动到不同的内存位置? [英] Does std::list guarantee that items will never be moved to a different memory location?

问题描述

是否保证一旦std::list 或std::forward_list 项被分配，它会一直保持在相同的内存位置(地址)直到被销毁?当然，除了列表本身被复制.

Is it guaranteed that once std::list or std::forward_list item is allocated, it will remain at the same memory location (address) until destroyed? Except, of course, for the list itself being copied.

推荐答案

如果您查看所有不破坏元素的函数的文档， (插入、emplace、push_back 等...)，你会看到他们有一个注释，"没有引用无效"，这相当于您所要求的(对象停留在相同的内存位置).所以，是的.

If you look at the documentation for all the functions which don't destroy elements, (insert, emplace, push_back, etc...), you will see that they have a note that "no references are invalidated", which is equivalent to what you are asking (objects staying at the same memory location). So, yes.

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