将字符串截断为字符串的前 n 个字符，如果删除了任何字符，则添加三个点 [英] Truncate a string to first n characters of a string and add three dots if any characters are removed

问题描述

如何在 PHP 中获取字符串的前 n 个字符?将字符串修剪为特定数量的字符并在需要时附加..."的最快方法是什么?

How can I get the first n characters of a string in PHP? What's the fastest way to trim a string to a specific number of characters, and append '...' if needed?

推荐答案

//The simple version for 10 Characters from the beginning of the string
$string = substr($string,0,10).'...';

更新:

基于检查长度的建议(并确保修剪和未修剪字符串的长度相似):

Based on suggestion for checking length (and also ensuring similar lengths on trimmed and untrimmed strings):

$string = (strlen($string) > 13) ? substr($string,0,10).'...' : $string;

所以你会得到一个最多 13 个字符的字符串；13 个(或更少)普通字符或 10 个字符后跟..."

So you will get a string of max 13 characters; either 13 (or less) normal characters or 10 characters followed by '...'

更新 2:

或者作为函数:

function truncate($string, $length, $dots = "...") {
    return (strlen($string) > $length) ? substr($string, 0, $length - strlen($dots)) . $dots : $string;
}

更新 3:

我写这个答案已经有一段时间了，我实际上不再使用这段代码了.我更喜欢这个功能，它使用 wordwrap 函数防止在单词中间破坏字符串:

It's been a while since I wrote this answer and I don't actually use this code any more. I prefer this function which prevents breaking the string in the middle of a word using the wordwrap function:

function truncate($string,$length=100,$append="…") {
  $string = trim($string);

  if(strlen($string) > $length) {
    $string = wordwrap($string, $length);
    $string = explode("\n", $string, 2);
    $string = $string[0] . $append;
  }

  return $string;
}

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