如何在python中将字符串转换为有效的变量名? [英] how do I convert a string to a valid variable name in python?

问题描述

我需要将任意字符串转换为python中有效变量名的字符串.

这是一个非常基本的例子:

s1 = 'name/with/slashes's2 = '姓名'定义清洁:s = s.replace('/','')s = s.strip()返回print clean(s1)+'_'#the _ is there所以我可以看到字符串的结尾

这是一种非常幼稚的方法.我需要检查字符串是否包含无效变量名字符并替换为 ''

pythonic 的方法是什么?

解决方案

根据 Python，标识符是一个字母或下划线，后跟无限的字母、数字和下划线组成的字符串:

导入重新定义清洁:# 删除无效字符s = re.sub('[^0-9a-zA-Z_]', '', s)# 删除前导字符，直到找到字母或下划线s = re.sub('^[^a-zA-Z_]+', '', s)返回

像这样使用:

<预><代码>>>>干净('32v2 g #Gmw845h$W b53wi')'v2gGmw845hWb53wi'

I need to convert an arbitrary string to a string that is a valid variable name in python.

Here's a very basic example:

s1 = 'name/with/slashes'
s2 = 'name '

def clean(s):
    s = s.replace('/','')
    s = s.strip()
    return s

print clean(s1)+'_'#the _ is there so I can see the end of the string

That is a very naive approach. I need to check if the string contains invalid variable name characters and replace them with ''

What would be a pythonic way to do this ?

解决方案

According to Python, an identifier is a letter or underscore, followed by an unlimited string of letters, numbers, and underscores:

import re

def clean(s):

   # Remove invalid characters
   s = re.sub('[^0-9a-zA-Z_]', '', s)

   # Remove leading characters until we find a letter or underscore
   s = re.sub('^[^a-zA-Z_]+', '', s)

   return s

Use like this:

>>> clean(' 32v2 g #Gmw845h$W b53wi ')
'v2gGmw845hWb53wi'

这篇关于如何在python中将字符串转换为有效的变量名?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！