python - 如何将退格符应用于字符串 [英] python - how to apply backspaces to a string

问题描述

我有一个字符串

s = '--two \x08--three'

当我打印时，我得到

--二--三

但是我可以做点什么吗

s='--二--三'

无需明确声明.

我不需要存储甚至不知道后退空间.我只想在没有退格字符的情况下操作文本.我怎样才能做到这一点?

希望我能澄清一点.假设我有两个字符串

test1 = 'a\bb' #btest2 = 'b' #b

当它们被打印出来时，它们等同于用户，但是test1!=test2.我正在做的是从终端拉出一些输出.此输出始终具有退格键.我希望能够操作最终结果、搜索单词、编辑字符串而不必担心退格.

编辑 2:我想我真正想要的是将变量设置为打印语句的结果

a = print("5\bA") #a='A' #不会像这样工作

解决方案

您可以使用正则表达式对字符串应用退格:

导入重新def apply_backspace(s):为真:# 如果你发现一个字符后跟一个退格，删除两个t = re.sub('.\b', '', s, count=1)如果 len(s) == len(t):# 现在删除字符串开头的所有退格return re.sub('\b+', '', t)s = t

现在:

<预><代码>>>>apply_backspace('abc\b\b\b123')'123'

I have a string

s = '--two \x08--three'

When I print, I get

--two--three

but can I do something to have

s='--two--three'

with out declaring it explicitly.

I do not need to store or even know about the back spaces. I just want to manipulate the text without the backspace characters there. How can I achieve this?

Edit: Hopefully I can clarify a little. Say I have two strings

test1 = 'a\bb' #b
test2 = 'b' #b

When they are printed, they are equivalent to the user, but test1!=test2. What I am doing is pulling some output from a terminal. This output has backspaces throughout. I want to be able to manipulate the end result, search for words, edit the string without worrying about the backspaces.

Edit 2: I guess what I really want is to set a variable as the result of a print statement

a = print("5\bA") #a='A' #does not work like this

解决方案

You can apply backspaces to a string using regular expressions:

import re

def apply_backspace(s):
    while True:
        # if you find a character followed by a backspace, remove both
        t = re.sub('.\b', '', s, count=1)
        if len(s) == len(t):
            # now remove any backspaces from beginning of string
            return re.sub('\b+', '', t)
        s = t

Now:

>>> apply_backspace('abc\b\b\b123')
'123'

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