替换数字后面的句点 [英] Replace period following a digit

问题描述

我遇到了一个看似简单的问题，但我找到的解决方案并不令人满意.我想用逗号替换任何后跟数字的句点.例如，

I've come across a problem that seems simple, yet solution I've found isn't satisfying. I want to replace any period followed by a number with a comma. For example,

strings <- c("22.222.222", "12.323", "don.t replace")

会成功转化为

[1] "22,222,222"    "12,323"        "don.t replace"

我尝试的第一个解决方案是

The first solution I attempted was

str_replace_all(strings,
                "(?<=\\d+)\\.",
                ",")

但我收到以下错误消息:

but I got the following error message:

Error in stri_replace_all_regex(string, pattern, replacement, vectorize_all = vec,  : 
 Look-Behind pattern matches must have a bounded maximum length. (U_REGEX_LOOK_BEHIND_LIMIT)

当我使用

str_replace_all(strings,
            "(?<=\\d{1,3})\\.",
            ",")

我得到了正确的转换.但是，硬编码的 1-3 位数字不是我想要的，我不明白为什么 \\d+ 不起作用但 \\d{1,3}确实如此.

I get the correct transformation. However, the hard-coded 1-3 digits is not what I want and I don't understand why \\d+ doesn't work but \\d{1,3} does.

推荐答案

不需要 + 量词，您只关心匹配序列中的最后一位数字.所以只需将 \d 放在lookbehind 中.

There's no need for the + quantifier, all you care about is matching the last digit in the sequence. So just put \d in the lookbehind.

str_replace_all(strings,
                "(?<=\\d)\\.",
                ",")

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