如何用连字符替换点、空格和逗号并避免使用 php 使用双连字符? [英] How to replace dots, spaces and commas with hyphen and avoid double hyphen using php?

问题描述

当我替换字符串的空格、点和逗号时，有时会出现双连字符.

When I replace spaces, dots and commas of a string, it sometimes happens that I get double hyphens.

例如将check out the 1. place 变成 check-out-the-1--place

我怎样才能避免这种情况?我希望它是 check-out-the-1-place - 这样每个单词之间只有一个连字符.这是我的代码:

How can I avoid that? I want it to be check-out-the-1-place - so that there only is one hyphen between each word. Here is my code:

str_replace([' ', ',', '.','?'], '-', strtolower($pathname));

现在，我知道为什么它会返回双连字符，但我不知道如何解决这个问题.

Right now, I know why it returns the double-hyphens, but I don't know how to work around that.

有人可以帮我吗?

推荐答案

我怎样才能避免这种情况?我希望它是 check-out-the-1-place - 这样每个单词之间只有一个连字符.这是我的代码:

How can I avoid that? I want it to be check-out-the-1-place - so that there only is one hyphen between each word. Here is my code:

虽然穆罕默德的答案几乎在那里，但这里有一个更完整的PCRE regex 方法及其工作原理的说明，因此您可以将其用作你需要:

Whilst Mohammad's answer is nearly there, here is a more fully working PCRE regex method and explanation as to how it works, so you can use it as you need:

$str = trim(strtolower($pathname));
$newStr = preg_replace('/[\s.,-]+/', '-', $str);

这是如何工作的:

• 匹配出现在下面列表中的单个字符 [\s.,-]+
  • + 量词在一次和无限次之间匹配，尽可能多次，根据需要回馈(贪婪)
  • \s 匹配任何空白字符(等于 [\r\n\t\f\v])
  • .,- 匹配列表中的单个字符 .,-(区分大小写)
  • 破折号 - 必须位于 [] 集的末尾.
  • Match a single character present in the list below [\s.,-]+
    • + Quantifier Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)
    • \s matches any whitespace character (equal to [\r\n\t\f\v])
    • .,- matches a single character in the list .,- (case sensitive)
    • The dash - must come at the end of the [] set.

    结果:

    这个:看看 1. 地方

    This: check out the 1. place

    变成:

    check-out-the-1-place
    

    还有

    这个:看看 - 1. 地方

    This: check out the - 1. place

    成为

    check-out-the-1-place

    我会更进一步，假设您将它用于 URL slug (什么?！);从字符串中去除所有 非字母数字字符，并按照典型的网站 slug 替换为单个 -.

    I would go further and assuming you are using this for a URL slug (a what?!); strip out all non-alphanumeric characters from the string and replace with a single - as per typical website slugs.

     $newStr = preg_replace('/[^a-z0-9]+/i', '-', $str);
    

    这是如何工作的:

    • 匹配出现在[a-z0-9]+下方列表中的单个字符NOT (^)
      • + 量词在一次和无限次之间匹配，尽可能多次，根据需要回馈(贪婪)
      • a-z a(索引 97)和 z(索引 122)之间范围内的单个字符(区分大小写)
      • 0-9 0(索引 48)和 9(索引 57)之间范围内的单个字符(区分大小写)
      • 末尾的i表示判断不区分大小写.
      • Match a single character NOT (^) present in the list below [a-z0-9]+
        • + Quantifier Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)
        • a-z a single character in the range between a (index 97) and z (index 122) (case sensitive)
        • 0-9 a single character in the range between 0 (index 48) and 9 (index 57) (case sensitive)
        • The i at the end indicates the judgements are case In-sensitive.

        示例:

        退房 - 没有！1. 放置

        check out - the no.! 1. Place

        变成:

        check-out-the-1-Place

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