有没有办法在不使用构造函数的情况下初始化结构的成员? [英] Is there a way to initialize members of a struct without using a constructor?

问题描述

我有一个包含两个列表的 struct:

I have a struct that contains two lists:

struct MonthData
{
   public List<DataRow> Frontline;
   public List<DataRow> Leadership;
}

但是，我想在创建结构时对两者进行初始化.如果我尝试:

However, I want to initialize both when the struct is created. If I try:

struct MonthData
{
   public List<DataRow> Frontline = new List<DataRow>();
   public List<DataRow> Leadership = new List<DataRow>();
}

然后我得到:

Error   23  'MonthData.Frontline': cannot have instance field initializers in structs
...

由于结构不能有无参数构造函数，我也不能只在构造函数中设置它.到目前为止，我只能看到以下选项:

Since structs cannot have parameterless constructors, I can't just set this in a constructor either. So far, I can only see the following options:

1. 在创建 MonthData 实例时初始化这两个属性
2. 使用类而不是结构
3. 创建一个带参数的构造函数并使用它
4. 为初始化它们的属性制作 getter 和 setter懒洋洋的.

推荐的方法是什么?现在，我认为将它作为一个类是最好的主意.

What is the recommended approach for this? Right now, I'm thinking making this a class is the best idea.

推荐答案

你应该使用类来代替.来自 MSDN:

You ought to use a class instead. From MSDN:

一般来说，类用于对更复杂的行为或打算在创建类对象后修改的数据进行建模.结构最适合包含主要数据的小型数据结构，这些数据在结构创建后不会被修改.

In general, classes are used to model more complex behavior, or data that is intended to be modified after a class object is created. Structs are best suited for small data structures that contain primarily data that is not intended to be modified after the struct is created.

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