搜索Java中的2维数组 [英] search a 2 dimensional array in java

问题描述

如何通过一个两维数组搜索[] [名]做一件迭代？

How does one iterate through a two dimensional array search for [ ] [Name]?

在名称找到了该指数应返回，这样我可以在阵列中更改的值。

When the Name is found the Index should be returned so that I can change the values in that array.

[索引] [价值观]

[Index] [Values].

此外，如何语法查找存储的阵列发现的？ [] [索引]。遍历指数和设置的值。 [0] [1] =等等。

Also, how does the syntax look for the storing to the array found? [ ] [index]. Loop through index and set a value. [0] [1] = blah.

感谢

推荐答案

有时更容易和更清洁总是把搜索结果在一个单独的方法：

Sometimes it's easier and always cleaner to put the search in a separate method:

 private Point find2DIndex(Object[][] array, Object search) {

    if (search == null || array == null) return null;

    for (int rowIndex = 0; rowIndex < array.length; rowIndex++ ) {
       Object[] row = array[rowIndex];
       if (row != null) {
          for (int columnIndex = 0; columnIndex < row.length; columnIndex++) {
             if (search.equals(row[columnIndex])) {
                 return new Point(rowIndex, columnIndex);
             }
          }
       }
    }
    return null; // value not found in array
 }

这将只返回第一个匹配。如果你需要的所有，收集所有点列表，并在年底返回列表。

This will return the first match only. If you need all, collect all points in a List and return that list at the end.

用法：

private void doSomething() {
  String[][] array = {{"one", "1"},{"two","2"}, {"three","3"}};
  Point index = find2DIndex(array, "two");

  // change one value at index
  if (index != null)
     array[index.x][index.y] = "TWO";

  // change everything in the whole row
  if (index != null) {
     String[] row = array[index.x];
     // change the values in that row
  }

}

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