与超类变量同名的子类变量 [英] Subclass variables with the same name of superclass ones

问题描述

是否有可能不覆盖发生?例如:

Is it possible for no override for happen? For example:

class A:
    def __init__(self, name):
        self.name = name

class B(A):
    def __init__(self, name):
        A.__init__(self, name)
        self.name = name + "yes"

B 类中的 self.name 有没有办法独立于 A 类中的 self.name ，或者必须使用不同的名称?

Is there any way for self.name in class B to be independent from that of Class A's, or is it mandatory to use different names?

推荐答案

使用两个下划线作为前缀会导致名称混淆，这似乎正是您想要的.例如

Prefixing a name with two underscores results in name mangling, which seems to be what you want. for example

class A:
    def __init__(self, name):
        self.__name = name

    def print_name(self):
        print self.__name


class B(A):
    def __init__(self, name):
        A.__init__(self, name)
        self.__name = name + "yes"

    def print_name(self):
        print self.__name

    def print_super_name(self):
        print self._A__name #class name mangled into attribute

在类定义中，您可以正常寻址__name(如在print_name 方法中).在子类中，以及类定义之外的任何其他地方，类的名称被修改为带有前导下划线的属性名称.

within the class definition, you can address __name normally (as in the print_name methods). In subclasses, and anywhere else outside of the class definition, the name of the class is mangled into the attribute name with a preceding underscore.

b = B('so')
b._A__name = 'something'
b._B__name = 'something else'

在您发布的代码中，子类属性将覆盖超类的name，这通常是您想要的.如果您希望它们分开，但具有相同的变量名称，请使用下划线

in the code you posted, the subclass attribute will override the superclass's name, which is often what you'd want. If you want them to be separate, but with the same variable name, use the underscores

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