如何生成一个单独的 python 进程? [英] How do I spawn a separate python process?

问题描述

我需要生成一个单独的运行子脚本的 python 进程.

I need to spawn a separate python process that runs a sub script.

例如:

main.py 运行并将一些输出打印到控制台.然后它生成 sub.py，它启动一个新进程.一旦 main.py 产生了 sub.py，它应该终止，而 sub.py 继续运行.

main.py runs and prints some output to the console. It then spawns sub.py which starts a new process. Once main.py has spawned sub.py it should terminate whilst sub.py continues to run.

谢谢.

当我运行 main.py 时，它会打印main.py"，但没有其他内容，并且 sub.py 不会启动.

When I run main.py it prints 'main.py' but nothing else and sub.py doesn't launch.

main.py

print "main.py"

import subprocess as sp
process=sp.Popen('sub.py', shell=True, stdout=sp.PIPE, stderr=sp.PIPE)
out, err = process.communicate(exexfile('sub.py'))  # The output and error streams

raw_input("Press any key to end.")

子.py

print "sub.py"
raw_input("Press any key to end.")

推荐答案

execfile

直截了当的方法:

execfile

The straightforward approach:

execfile('main.py')

子流程

提供对输入和输出的细粒度控制，可以在后台运行进程:

Subprocess

Offers fine-grained control over input and output, can run processes in background:

import subprocess as sp
process=sp.Popen('other_file.py', shell=True, stdout=sp.PIPE, stderr=sp.PIPE)
out, err = process.communicate()  # The output and error streams.

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