subprocess.Popen('start') 失败 [英] subprocess.Popen('start') fails

问题描述

在 python 中运行它会导致一个 WindowsError，指出它找不到指定的文件

Running this in python will result in a WindowsError stating it cannot find the specified file

失败:

import subprocess

subprocess.Popen('start notepad.exe')

在命令窗口中，它可以工作

In a command window, it works

start notepad.exe

我猜它是 Windows 无法找到 start[.exe?] 的路径问题，它位于何处，以便我可以将其添加到路径中或仅将其包含在 Popen 调用中.

Im guessing its a path thing where windows can't locate start[.exe?] Where is this located so i can add it in the path or just include it in the Popen call.

谢谢

推荐答案

我不完全确定 start 是一个程序.我认为这可能是 CMD shell 的内置命令.试试

I'm not entirely sure start is a program. I think it might be a built-in command of the CMD shell. Try

subprocess.Popen('cmd /c start notepad.exe')

此外，任何不使用 just 的原因:

Also, any reason why not use just:

subprocess.Popen('notepad.exe')

这篇关于subprocess.Popen('start') 失败的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！