JS中的数独求解器 [英] Sudoku solver in JS

问题描述

我正在尝试编写一种可以解决数独的算法.现在，我的代码可以工作，直到 supplyGrid 没有数字为止.当它发生时，它应该返回并尝试另一个号码，对吗?老实说，我不知道如何做到这一点.

I'm trying to write an algorithm that can solve sudoku. For now, my code works till supplyGrid is out of numbers. When it happens it should go back and try another number, right? To be honest I have no clue how to achive that.

var grid = [
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0]
],
    supplyGrid = [1, 2, 3, 4, 5, 6, 7, 8, 9],
    row = 0,
    col = 0,
    value = 0,
    index = 0;


var solveSudoku = function (grid, row, col) {
    if (col > 8) {
        row++;
        col = 0;
        if (row > 8 && col > 8) {
            console.log(grid);
            return;
        }
    }
    if (grid[row][col] === 0) { //
        index = Math.floor(Math.random() * supplyGrid.length);
        value = supplyGrid[index];
        if (isValid(row, col, value)) {
            grid[row][col] = value;
            col++;
            supplyGrid = [1, 2, 3, 4, 5, 6, 7, 8, 9];
            solveSudoku(grid, row, col);
        } else {
            supplyGrid.splice(index, 1);
            console.log(supplyGrid);
            if (supplyGrid.length < 1) { 
                //backtrack();
                console.log('Out of numbers');
                return;
            }
            solveSudoku(grid, row, col);
        }
    } else { //row = 3, col = 5
        solveSudoku(grid, row, ++col);
    }
    return this;
}

function isValid(row, col, value) {
    if ((validateColumn(row, col, value)) || (validateRow(row, col, value)) || (validateBox(row, col, value))) {
        return false;
    } else {
        return true;
    }
}

function validateBox(row, col, value) {
    row = Math.floor(row / 3) * 3;
    col = Math.floor(col / 3) * 3;
    var isFound = false;
    for (var i = 0; i < 3; i++) {
        for (var j = 0; j < 3; j++) {
            if (grid[row + i][col + j] == value) isFound = true;
        }
    }
    return isFound;
}

function validateRow(row, col, value) { 
    var isFound = false;
    for (var i = 0; i < 9; i++) {
        if (grid[row][i] === value) isFound = true;
    }
    return isFound;
}

function validateColumn(row, col, value) { 
    var isFound = false;
    for (var i = 0; i < 9; i++) {
        if (grid[i][col] === value) isFound = true;
    }
    return isFound;
}

推荐答案

我用回溯算法解决了这个问题:

I solved this question with backtracking algorithm:

const _board = [
    ['.', '9', '.', '.', '4', '2', '1', '3', '6'],
    ['.', '.', '.', '9', '6', '.', '4', '8', '5'],
    ['.', '.', '.', '5', '8', '1', '.', '.', '.'],
    ['.', '.', '4', '.', '.', '.', '.', '.', '.'],
    ['5', '1', '7', '2', '.', '.', '9', '.', '.'],
    ['6', '.', '2', '.', '.', '.', '3', '7', '.'],
    ['1', '.', '.', '8', '.', '4', '.', '2', '.'],
    ['7', '.', '6', '.', '.', '.', '8', '1', '.'],
    ['3', '.', '.', '.', '9', '.', '.', '.', '.'],
];
sodokoSolver(_board);
console.log(_board);

function isValid(board, row, col, k) {
    for (let i = 0; i < 9; i++) {
        const m = 3 * Math.floor(row / 3) + Math.floor(i / 3);
        const n = 3 * Math.floor(col / 3) + i % 3;
        if (board[row][i] == k || board[i][col] == k || board[m][n] == k) {
          return false;
        }
    }
    return true;
}


function sodokoSolver(data) {
  for (let i = 0; i < 9; i++) {
    for (let j = 0; j < 9; j++) {
      if (data[i][j] == '.') {
        for (let k = 1; k <= 9; k++) {
          if (isValid(data, i, j, k)) {
            data[i][j] = `${k}`;
          if (sodokoSolver(data)) {
           return true;
          } else {
           data[i][j] = '.';
          }
         }
       }
       return false;
     }
   }
 }
 return true;
}

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