Inno Setup的:如何定义常量数组? [英] Inno Setup: How to define an array in const?
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问题描述
我有一些问题定义字符串数组常量
下的创新安装了code节,我有以下几点:
I'm having some problems defining an array of strings in const
under the code section in Inno Setup, I have the following:
[Code]
const
listvar: array [0..4] of string =
('one', 'two', 'three', 'four', 'five');
它说我需要一个 =
其中:
是,但我不能将其定义为数组。
It's saying I need an =
where the :
is, but then I can't define it as an array.
推荐答案
我前一阵做了一个小工具的功能。它不会让你一个恒定分配一个数组,但它可以在一个单行的变量做的伎俩。希望这帮助。
I made a little utility function a little while ago. It won't allow you to assign an array on a constant but it could do the trick for a variable in a one liner. Hoping this help.
您可以用这种方式:
listvar := Split('one,two,three,four,five', ',');
// ============================================================================
// Split()
// ----------------------------------------------------------------------------
// Split a string into an array using passed delimeter.
// ============================================================================
Function Split(Expression: String; Separator: String): TArrayOfString;
Var
i: Integer;
tmpArray : TArrayOfString;
curString : String;
Begin
i := 0;
curString := Expression;
Repeat
SetArrayLength(tmpArray, i+1);
If Pos(Separator,curString) > 0 Then Begin
tmpArray[i] := Copy(curString, 1, Pos(Separator, curString)-1);
curString := Copy(curString, Pos(Separator,curString) + Length(Separator), Length(curString));
i := i + 1;
End Else Begin
tmpArray[i] := curString;
curString := '';
End;
Until Length(curString)=0;
Result:= tmpArray;
End;
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