Swagger 生成器无法识别控制器 [英] Swagger generator doesn't recognize controller

问题描述

我有这个 yaml 文件:

I have this yaml file:

---
swagger: "2.0"
info:
  version: 0.1.0
  title: "My API"
host: localhost:3000
basePath: /api
schemes:
  - http
paths:
    /weather:
      get:
        x-swagger-router-controller: "weatherController"
        description: "Returns current weather in the specified city to the caller"
        operationId: getWeather
        parameters:
          - name: city
            in: query
            description: "The city you want weather for in the form city,state,country"
            required: true
            type: "string"

当我运行 swagger-codegen-cli 时，生成/api/Default.js 和/api/DefaultService.js ，但没有/api/weatherController.js.

When I run swagger-codegen-cli, generates /api/Default.js and /api/DefaultService.js , but no /api/weatherController.js.

我也试过这个:

---
swagger: "2.0"
info:
  version: 0.1.0
  title: "My API"
host: localhost:3000
basePath: /api
schemes:
  - http
paths:
    /weather:
      x-swagger-router-controller: "weatherController"
      get:
        description: "Returns current weather in the specified city to the caller"
        operationId: getWeather
        parameters:
          - name: city
            in: query
            description: "The city you want weather for in the form city,state,country"
            required: true
            type: "string"

我用这个命令运行生成器:

And I run the generator with this command:

java -jar swagger-codegen-cli.jar generate -l nodejs-server -o output -i api.yaml

我该怎么做?

推荐答案

我认为这是一个错误，如果您能将其归档到 swagger-codegen 项目中，那就太好了.但作为一种解决方法，请考虑添加一个标签:

I think that's a bug, it would be great if you could file that on the swagger-codegen project. But as a work around, consider adding a tag:

/weather:
  x-swagger-router-controller: "weatherController"
  get:
    tags:
    - weatherController
    description: "Returns current weather in the specified city to the caller"
    operationId: getWeather
    parameters:
      - name: city
        in: query
        description: "The city you want weather for in the form city,state,country"
        required: true
        type: "string"

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