比较和筛选两个数组 [英] Comparing and Filtering two arrays

问题描述

我一直想在那里有两个数组给实现一个函数，

I've been trying to implement a function where given with two arrays,

数组1 的元素作为条件，筛选出在元素的数组2

array1's elements is used as conditions to filter out elements in array2.

例如：

array1= [apple, grapes, oranges]

array2= [potato, pears, grapes, berries, apples, oranges]

送入一个函数之后，数组2应具有元素作为这样：

After feeding into a function, array2 should have elements as such:

filter_twoArrays(array1,array2)

array2= [grapes, apples, oranges]

我试过以下code，使用循环和方法Array.splice（），但我看到的问题是，当我用拼接的方法，似乎它改变的数组2的长度循环：

I've tried the following code, using for loops and array.splice(), but the problem I am seeing is that when I use the splice method, it seems that it changes the lengths of array2 in the for loop:

function filter_twoArrays(filter,result){

  for(i=0; i< filter.length; i++){
    for(j=0; j< result.length; j++){
      if(filter[i] !== result[j]){
        result.splice(j,1)
      }
    }
  }

任何输入将pciated如何完善过滤功能大大AP $ P $

Any inputs will be greatly appreciated on how to refine the filter function

干杯！

推荐答案

标志，它是通过被过滤掉的项目删除结果[指数] 根据需要操纵它们。

Mark the items which are to be filtered out via delete result[index] manipulate them as needed.

的的JavaScript 的

window.onload = runs;

function runs() {
    var array1 = ["apples", "grapes", "oranges"];
    var array2 = ["potato", "pears", "grapes", "berries", "apples", "oranges"];
    var result = filter_twoArrays(array1, array2);

    function filter_twoArrays(filter, result) {
        var i = 0,
            j = 0;
        for (i = 0; i < result.length; i++) {
            var FLAG = 0;
            for (j = 0; j < filter.length; j++) {
                if (filter[j] == result[i]) {
                    FLAG = 1;
                }
            }
            if (FLAG == 0) delete result[i];
        }
        return result;
    }

    var body = document.getElementsByTagName("body")[0];
    var i = 0;
    for (i = 0; i < result.length; i++) {
        if (result[i] !== undefined)
            body.innerHTML = body.innerHTML + result[i] + " ";
    }
}

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