如何创建波浪路径 Swift [英] How to create a wave path Swift

问题描述

我希望我的节点以正弦曲线波行进，并且我尝试将其用于 CGPath.如何创建遵循正弦曲线的 CGPath?除了手动找到曲线上的点，还有其他方法吗，或者我可以传入一个正弦函数?

I want my node to travel in a sine curve wave, and I tried using that for CGPath. How do I create a CGPath that follows a sine curve? Is there any way other than to manually find the points on the curve, or could I just pass in a sine function?

let action = SKAction.followPath(<正弦路径>, asOffset: true, orientToPath: true, duration: 5)

这可以通过 Bezier Paths 完成，然后转换为 CGPaths 吗?谢谢.

Could this be done through Bezier Paths and then converted into CGPaths? Thanks.

推荐答案

不，没有从函数构建路径的内置方法，但您可以轻松编写自己的方法.在 Swift 3 中:

No, there isn't a built in method to build a path from a function, but you can easily write one of your own. In Swift 3:

/// Build path within rectangle
///
/// Given a `function` that converts values between zero and one to another values between zero and one, this method will create `UIBezierPath` within `rect` using that `function`.
///
/// - parameter rect:      The `CGRect` of points on the screen.
///
/// - parameter count:     How many points should be rendered. Defaults to `rect.size.width`.
///
/// - parameter function:  A closure that will be passed an floating point number between zero and one and should return a return value between zero and one as well.

private func path(in rect: CGRect, count: Int? = nil, function: (CGFloat) -> (CGFloat)) -> UIBezierPath {
    let numberOfPoints = count ?? Int(rect.size.width)

    let path = UIBezierPath()
    path.move(to: convert(point: CGPoint(x: 0, y: function(0)), in: rect))
    for i in 1 ..< numberOfPoints {
        let x = CGFloat(i) / CGFloat(numberOfPoints - 1)
        path.addLine(to: convert(point: CGPoint(x: x, y: function(x)), in: rect))
    }
    return path
}

/// Convert point with x and y values between 0 and 1 within the `CGRect`.
///
/// - parameter point:  A `CGPoint` value with x and y values between 0 and 1.
/// - parameter rect:   The `CGRect` within which that point should be converted.

private func convert(point: CGPoint, in rect: CGRect) -> CGPoint {
    return CGPoint(
        x: rect.origin.x + point.x * rect.size.width,
        y: rect.origin.y + rect.size.height - point.y * rect.size.height
    )
}

所以，让我们传递一个函数，当它沿着 rect 的 width 前进时，它会做一条正弦曲线:

So, let's pass a function that does one sine curve as it progresses across the width of the of the rect:

func sinePath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    // note, since sine returns values between -1 and 1, let's add 1 and divide by two to get it between 0 and 1
    return path(in: rect, count: count) { (sin($0 * .pi * 2.0) + 1.0) / 2.0 }
}

注意，上面假设你想从左到右遍历，构建函数定义的路径.您还可以做更多的参数化再现:

Note, the above assumed that you wanted traverse from left to right, building the path defined by the function. You could also do more of a parametric rendition:

/// Build path within rectangle
///
/// Given a `function` that converts values between zero and one to another values between zero and one, this method will create `UIBezierPath` within `rect` using that `function`.
///
/// - parameter rect:      The `CGRect` of points on the screen.
///
/// - parameter count:     How many points should be rendered. Defaults to `rect.size.width` or `rect.size.width`, whichever is larger.
///
/// - parameter function:  A closure that will be passed an floating point number between zero and one and should return a `CGPoint` with `x` and `y` values between 0 and 1.

private func parametricPath(in rect: CGRect, count: Int? = nil, function: (CGFloat) -> (CGPoint)) -> UIBezierPath {
    let numberOfPoints = count ?? max(Int(rect.size.width), Int(rect.size.height))

    let path = UIBezierPath()
    let result = function(0)
    path.move(to: convert(point: CGPoint(x: result.x, y: result.y), in: rect))
    for i in 1 ..< numberOfPoints {
        let t = CGFloat(i) / CGFloat(numberOfPoints - 1)
        let result = function(t)
        path.addLine(to: convert(point: CGPoint(x: result.x, y: result.y), in: rect))
    }
    return path
}

然后你可以使用正弦曲线修改x坐标，只需增加y:

Then you can modify the x coordinate using sine curve, and just increment y:

func verticalSinePath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    // note, since sine returns values between -1 and 1, let's add 1 and divide by two to get it between 0 and 1
    return parametricPath(in: rect, count: count) { CGPoint(
        x: (sin($0 * .pi * 2.0) + 1.0) / 2.0,
        y: $0
    ) }
}

这样做的好处是您现在还可以定义您想要的任何类型的路径，例如一个螺旋:

The virtue of this is that you could also now define any sort of path you want, e.g. a spiral:

func spiralPath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    return parametricPath(in: rect, count: count) { t in
        let r = 1.0 - sin(t * .pi / 2.0)
        return CGPoint(
            x: (r * sin(t * 10.0 * .pi * 2.0) + 1.0) / 2.0,
            y: (r * cos(t * 10.0 * .pi * 2.0) + 1.0) / 2.0
        )
    }
}

<小时>

以下是上述 Swift 2 版本:

---

Here are the Swift 2 renditions of the above:

/// Build path within rectangle
///
/// Given a `function` that converts values between zero and one to another values between zero and one, this method will create `UIBezierPath` within `rect` using that `function`.
///
/// - parameter rect:      The `CGRect` of points on the screen.
///
/// - parameter count:     How many points should be rendered. Defaults to `rect.size.width`.
///
/// - parameter function:  A closure that will be passed an floating point number between zero and one and should return a return value between zero and one as well.

private func path(in rect: CGRect, count: Int? = nil, function: (CGFloat) -> (CGFloat)) -> UIBezierPath {
    let numberOfPoints = count ?? Int(rect.size.width)

    let path = UIBezierPath()
    path.moveToPoint(convert(point: CGPoint(x: 0, y: function(0)), rect: rect))
    for i in 1 ..< numberOfPoints {
        let x = CGFloat(i) / CGFloat(numberOfPoints - 1)
        path.addLineToPoint(convert(point: CGPoint(x: x, y: function(x)), rect: rect))
    }
    return path
}

/// Convert point with x and y values between 0 and 1 within the `CGRect`.
///
/// - parameter point:  A `CGPoint` value with x and y values between 0 and 1.
/// - parameter rect:   The `CGRect` within which that point should be converted.

private func convert(point point: CGPoint, rect: CGRect) -> CGPoint {
    return CGPoint(
        x: rect.origin.x + point.x * rect.size.width,
        y: rect.origin.y + rect.size.height - point.y * rect.size.height
    )
}

func sinePath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    // note, since sine returns values between -1 and 1, let's add 1 and divide by two to get it between 0 and 1
    return path(in: rect, count: count) { (sin($0 * CGFloat(M_PI * 2.0)) + 1.0) / 2.0 }
}

/// Build path within rectangle
///
/// Given a `function` that converts values between zero and one to another values between zero and one, this method will create `UIBezierPath` within `rect` using that `function`.
///
/// - parameter rect:      The `CGRect` of points on the screen.
///
/// - parameter count:     How many points should be rendered. Defaults to `rect.size.width`.
///
/// - parameter function:  A closure that will be passed an floating point number between zero and one and should return a `CGPoint` with `x` and `y` values between 0 and 1.

private func parametricPath(in rect: CGRect, count: Int? = nil, function: (CGFloat) -> (CGPoint)) -> UIBezierPath {
    let numberOfPoints = count ?? max(Int(rect.size.width), Int(rect.size.height))

    let path = UIBezierPath()
    let result = function(0)
    path.moveToPoint(convert(point: CGPoint(x: result.x, y: result.y), rect: rect))
    for i in 1 ..< numberOfPoints {
        let t = CGFloat(i) / CGFloat(numberOfPoints - 1)
        let result = function(t)
        path.addLineToPoint(convert(point: CGPoint(x: result.x, y: result.y), rect: rect))
    }
    return path
}

func verticalSinePath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    // note, since sine returns values between -1 and 1, let's add 1 and divide by two to get it between 0 and 1
    return parametricPath(in: rect, count: count) { CGPoint(
        x: (sin($0 * CGFloat(M_PI * 2.0)) + 1.0) / 2.0,
        y: $0
    ) }
}

func spiralPath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    return parametricPath(in: rect, count: count) { t in
        let r = 1.0 - sin(t * CGFloat(M_PI_2))
        return CGPoint(
            x: (r * sin(t * 10.0 * CGFloat(M_PI * 2.0)) + 1.0) / 2.0,
            y: (r * cos(t * 10.0 * CGFloat(M_PI * 2.0)) + 1.0) / 2.0
        )
    }
}

这篇关于如何创建波浪路径 Swift的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！