基于子的价值在合并数组对象 [英] Merging objects in array based on sub-value

问题描述

我有填充对象的数组。我如何去了解这个数组中合并对象时，他们有一个匹配的特定子价值？

I have an array populated with objects. How do I go about merging objects inside this array when they have a matching specific sub value?

我的数组是这样的：

var data = [
    {
        prod_name:"test1", type:"1", color:"white", product_id:"5"
    },
    {
        prod_name:"test2", type:"1", color:"green", product_id:"7"
    },
    {
        prod_name:"test2", type:"2", color:"green", product_id:"7"
    },
    {
        prod_name:"test3", type:"4", color:"red", product_id:"8"
    },
    {
        prod_name:"test4", type:"2", color:"white", product_id:"21"
    }    
];

我想根据匹配的合并对象的product_id 。

在情况下，值是不一样的，我想保持这两个值，用逗号分隔。因此，previous数组的结果将变成：

In case the values are not the same, I want to keep BOTH values, seperated with a comma. So the outcome of the previous array would become:

[
    {
        prod_name:"test1", type:"1", color:"white", product_id:"5"
    },
    {
        prod_name:"test2", type:"1,2", color:"green", product_id:"7"
    },
    {
        prod_name:"test3", type:"4", color:"red", product_id:"8"
    },
    {
        prod_name:"test4", type:"2", color:"white", product_id:"21"
    }    
];

该阵列缩水1，因为它有一个重复的，而这两个值，凡不一样的由逗号类型合并，分开：1,2

我以为可以如下：

jQuery.each( data, function( i, val ) {
    var productID = val.product_id;
    var index_key = i;
    jQuery.each( data, function( i, val ) {
        if(val.product_id == productID && data[index_key] != data[i]){
            jQuery.extend(data[index_key], data[i]);
        }
    });
});

但是，这仅覆盖键入第一个撞价值，并保持这两个条目。

But this only overwrites the type value of the first hit and keeps both entries.

有关mergable项的值 PROD_NAME 和的product_id 都是一样的。

For "mergable" items the values prod_name and product_id are always the same.

有谁知道的一种方式，以达到预期的效果？

Does anyone know of a way to achieve the desired result?

更新：
不同的值（产品属性）可能在稍后的阶段加入。为此我preFER不专门检查键入属性的方法，而是检查eveything这不是的product_id 或 PROD_NAME ，如果它有一个命中，合并了这个用逗号。

UPDATE: Different values(product attributes) might be added in a later stage. Therefor I'd prefer a method that does not specifically check for the type attribute, but rather checks for eveything that is NOT product_id or prod_name and if it has a hit, merges this with a comma.

FIDDLE

FIDDLE

推荐答案

我在例如波纹​​管做的，首先我创建对象来实现唯一值（由 PROJECT_ID ） ，然后转换对象阵列。在第一个循环我检查，如果项目不水库存在 - 放 RES ，否则我只能更改属性类型

What I do in example bellow., first I create object to achieve unique values (by project_id), and then converted object to array. In first loop I check if item does not exists in res - put to res, else I change only property type

var res = {};

$.each(data, function (key, value) {
    if (!res[value.product_id]) {
        res[value.product_id] = value;    
    } else {
        res[value.product_id].type = [
          res[value.product_id].type, 
          value.type
        ].join(',');
    }
});

data = $.map(res, function (value) {
  return value;
}); 

console.log(data);

示例

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