将应用程序升级到 Swift 4 和 iOS 11 - TwitterKit 问题 [英] Upgrading App to Swift 4 and iOS 11 - TwitterKit Issues

问题描述

我正在尝试将我的应用升级到最新的 iOS 支持.我已经通过 CocoaPods 添加了 TwitterKit，并在我的 Bridge Header 中放置了标题.然而;我收到一条错误消息:

I'm trying to upgrade my app to latest iOS support. I've added TwitterKit via CocoaPods, and placed header in my Bridge Header. However; I am getting an error saying:

使用未解析的已识别Twitter" - 您的意思是TWTRTTwitter"吗.

Use of unresolved identified 'Twitter' - did you mean 'TWTRTTwitter'.

func application(_ application: UIApplication, didFinishLaunchingWithOptions lauunchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    Twitter.sharedInstance().start(withConsumerKey:"MYKEY", consumerSecret:"MYSECRET")
    return true
}

这是推特推荐的代码.我也在:

This right out of the Twitter recommended code. I also get it at:

func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {

    let handled:Bool = true

    Twitter.sharedInstance().application(app, open: url, options: options)

    return handled
}

有什么指点吗?

推荐答案

谢谢你，Andy Piper，我解决了以下问题:

Thank you, Andy Piper, I fixed the issue as following:

1. 更新了 pod，以便 TwitterCore 3.1.0 和 TwitterKit 3.3.0

1. Updated pod so that TwitterCore 3.1.0 and TwitterKit 3.3.0

在 Bridging-Header.h 文件中

In Bridging-Header.h file

导入为TwitterKit/TWTRKit.h 而不是TwitterKit/TwitterKit.h

imported as TwitterKit/TWTRKit.h instead of TwitterKit/TwitterKit.h

1. 在 didFinishLaunchingWithOptions 中，

1. In didFinishLaunchingWithOptions,

• 修改 Twitter.sharedInstance().start(withConsumerKey: 你的消费者密钥", consumerSecret:"你的消费者秘密")

TWTRTwitter.sharedInstance().start(withConsumerKey: 你的消费者密钥", consumerSecret:"你的消费者秘密")

TWTRTwitter.sharedInstance().start(withConsumerKey: "your consumer key", consumerSecret:"your consumer secret")

即在使用它的地方用 TWTRTwitter 替换 Twiter.

i.e replace Twiter with TWTRTwitter where it is used.

• 不需要用fabric初始化，所以去掉这行或者去掉

Fabric.with([Twitter.self]) 或 Fabric.with([TWTRTwitter.self])

Fabric.with([Twitter.self]) or Fabric.with([TWTRTwitter.self])

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