如何获取 JSpinner 中所选项目的值? [英] how can I get the value of a the selected item in a JSpinner?

问题描述

我正在制作一个使用最大数量为 30 的 JSpinner 的应用程序，我应该从这个 JSpinner 中选择一个值并将一个字符串粘贴到 JTextField 中，结果将出现在 Textarea 中，当我编译时我有很多问题关于 jSpinner1State 方法，任何人都可以帮助我，因为我不知道我的问题出在哪里.这是我的方法 JSpinner 的代码:

I'm making an application that uses a JSpinner with a max number 30,I should choose a value from this JSpinner and tape a String to the JTextField and the result will appear in the Textarea,when I compile I have many problems concerning the method jSpinner1State,can any one help me because I don't know where is my problem. This is my code of the method JSpinner:

    jSpinner1.addChangeListener(this);

    private void jSpinner1StateChanged(javax.swing.event.ChangeEvent evt) { 
    // TODO add your handling code here: 
    Object sp=jSpinner1.getValue();
    int i =Integer.parseInt(sp.toString() );
    String targetIP=jTextField1.getText();

        try{ 
    jSpinner1StateChanged(evt);
    String   cmd = "tracert -h "+i+ "" +targetIP;                        
    Process p = Runtime.getRuntime().exec(cmd);
    InputStream in = p.getInputStream();
    StringBuilder build = new StringBuilder();
    Reader reader = new InputStreamReader(in);
    char[] buffer = new char[512];
    int nbRead = reader.read(buffer);
    while(nbRead > 0) {
    build.append(buffer, 0, nbRead);
    nbRead = reader.read(buffer);
     }
    String response = build.toString(); 
    jTextArea1.setText(response);
    }catch(Exception e){
jTextArea1.append(e.toString()); }


}

推荐答案

首先，您的代码中似乎存在无限循环.在您的 jSpinner1StateChanged 函数中，您正在调用 jSpinner1StateChanged(evt)，这将导致无限循环.

For one, it appears you have an infinite loop in your code. Inside your jSpinner1StateChanged function, you are calling jSpinner1StateChanged(evt), which will cause an infinite loop.

你是如何创建你的 JSpinner 的?如果您使用的是整数，则使用 SpinnerNumberModel 创建它.从微调器中获取当前值时，这将简化您的代码.

How are you creating your JSpinner? If you're using ints, then create it by using a SpinnerNumberModel. This will simplify your code when getting the current value out of the spinner.

jSpinner1 = new JSpinner(new SpinnerNumberModel(0, 0, 30, 1));
Integer currentValue = (Integer)jSpinner1.getValue();

这篇关于如何获取 JSpinner 中所选项目的值?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！