复选框开关盒的实现 [英] Implementation of switch case for check box

问题描述

有什么方法可以实现复选框的 switch case?

Is there any way to implement switch case for checkbox?

例如:我有 4 个复选框，如果我选择了 2 个复选框，如何将 case 触发到我想要的输出?

Example: I have 4 checkboxes, if I selected 2 checkboxes, how to trigger the case to the output I want?

 double exam = 0.0, assign = 0.0, quiz = 0.0, ct = 0.0;

                if (examchkbox.isSelected()) {
                exam = Double.parseDouble(examtextfield.getText());
                }
                if(ctchkbox.isSelected()) {
                ct = Double.parseDouble(cttextfield.getText());    
                }
                if(quizchkbox.isSelected()) {
                quiz = Double.parseDouble(quiztextfield.getText());    
                }
                if(asschkbox.isSelected()) {
                assign = Double.parseDouble(asstextfield.getText());    
                }
                if (!(exam + ct + quiz + assign == 100)) {
                markerrorlbl.setText("Total marks must be 100");
                }
                else {  

                // implementation of code here
                }

这是设计视图.

假设我勾选了考试和课堂测试，我只想在文本字段中选择值并使用 switch case 存储标记.这可能吗?

Let say I ticked Exam and Class Test, I just want to select the value in the text field and store the marks by using switch case. Is that possible?

这就是我想要的，但我不知道如何使用 Checkbox 实现.

This is the thing about I want but I've no idea how to implement with Checkbox.

switch(x) 
        {
            case 1 : A = new exam(marks)   ;total+=marks;  break;
            case 2 : A = new test(marks)   ;total+=marks; break;
            case 3 : A = new quiz(marks)   ;total+=marks; break;
            case 4 : A = new assignment(marks) ;total+=marks;break;     
        }

推荐答案

为什么要使用 switch 而不是代码中已有的 if 语句?

Why do you want to use a switch instead of the if statements you already have in your code?

因为您可以相互独立地选择四个复选框，所以 switch 在这里不是最好的解决方案.您有四个复选框，因此有 2^4 = 16 种可能的检查模式":

Since you can select the four checkboxes independently from each other, a switch is not the best solution here. You have four checkboxes, so there are 2^4 = 16 possible "check patterns":

int pattern = (cb1.isSelected() ? 0b0001 : 0)
            | (cb2.isSelected() ? 0b0010 : 0)
            | (cb3.isSelected() ? 0b0100 : 0) 
            | (cb4.isSelected() ? 0b1000 : 0);

switch (pattern) {
    case 0b0001:
        // code for when only checkbox 1 is checked 
        break;
    ...
    case 0b0011:
        // code for when checkbox 1 and checkbox 2 are checked
        break;
    ...
    case 0b1011:
        // code for when only checkbox 1, 2 and 4 are checked
        break;
    ...
}

如果使用开关，则需要 16 个箱子.相比之下，你只需要 4 个 if 语句:

If you use a switch, you would need 16 cases. In contrast, you only need 4 if statements:

if (checkbox 1 is checked) {
    // code for when checkbox 1 is checked
}
if (checkbox 2 is checked) {
    // code for when checkbox 2 is checked 
}
...    

请注意，这是 4 个独立的 if 语句，没有 else if.

Note that these are 4 independent if statements, no else ifs there.

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