如何在 Symfony 2 中模拟 500 错误 [英] How to Simulate 500 Error in Symfony 2

问题描述

我想知道如何在 Symfony 2 中模拟 500 错误.

I am wondering how would I simulate a 500 error in Symfony 2.

我一直在阅读这篇博文，其中Raise建议抛出异常

I have been reading this post where Raise suggests throwing an exception

throw new sfException('测试 500 错误');

throw new sfException('Testing the 500 error');

在 Symfony 1.4 中.

in Symfony 1.4.

我一直把这段代码放在我的

I have been placing this code in my

\store\vendor\symfony\symfony\src\Symfony\Bundle\TwigBundle\Controller\ExceptionController.php

但我得到了致命错误

在第 49 行的/home/notroot/www/store/vendor/symfony/symfony/src/Symfony/Bundle/TwigBundle/Controller/ExceptionController.php 中找不到类Symfony\Bundle\TwigBundle\Controller\sfException"`

Class 'Symfony\Bundle\TwigBundle\Controller\sfException' not found in /home/notroot/www/store/vendor/symfony/symfony/src/Symfony/Bundle/TwigBundle/Controller/ExceptionController.php on line 49`

第 49 行是我添加的异常代码.

Line 49 refers to the exception code I added.

我的问题是在 Symfony 2 中抛出异常是否仍然可以强制出现 500 错误，如果是这样，我应该把这个异常放在哪里?

My question is if throwing an exception is still viable in forcing a 500 error in Symfony 2, and if so where do I put this exception?

如果这不再可行，我将如何测试错误 500?

If this is no longer viable, how would I be able to test for an error 500?

推荐答案

你可以这样做.

//in your controller
$response = new Response();
$response->setStatusCode(500);
return $response;

不要忘记添加

use Symfony\Component\HttpFoundation\Response;

在文件的顶部.

要强制 Symfony 500 错误，您的提议很好:

Edit : To force Symfony 500 error, your proposition is fine :

throw new \Exception('Something went wrong!');

把它放在一个控制器函数中.

Put it in a controller function.

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