无法确定属性“翻译"的访问类型在 Symfony 3.2.* 中,带有 Sonata 管理项目和 Sonata 翻译包 [英] Could not determine access type for property "translations" in Symfony 3.2.* with Sonata admin project and Sonata translation bundle
问题描述
我已经在 Symfony 3.2.* 版本中安装了 Sonata 管理项目.我的项目中使用的 composer.json 文件中的组件如下:
I have installed Sonata admin project in Symfony 3.2.* version. Components that are being used in my project from composer.json file are as following:
composer.json 文件的包片段
composer.json file's package snippet
"require": {
"php": ">=5.5.9",
"ext-pdo_sqlite": "*",
"a2lix/i18n-doctrine-bundle": "^0.1.0",
"a2lix/translation-form-bundle": "^2.1",
"doctrine/doctrine-bundle": "^1.6",
"doctrine/doctrine-cache-bundle": "^1.2",
"doctrine/doctrine-fixtures-bundle": "^2.2",
"doctrine/orm": "^2.5",
"erusev/parsedown": "^1.5",
"ezyang/htmlpurifier": "^4.7",
"friendsofsymfony/user-bundle": "~2.0@dev",
"incenteev/composer-parameter-handler": "^2.0",
"sensio/distribution-bundle": "^5.0",
"sensio/framework-extra-bundle": "^3.0.2",
"sonata-project/admin-bundle": "^3.12",
"sonata-project/doctrine-orm-admin-bundle": "^3.1",
"sonata-project/translation-bundle": "^2.1",
"stof/doctrine-extensions-bundle": "^1.2",
"symfony/monolog-bundle": "^3.0",
"symfony/polyfill-apcu": "^1.0",
"symfony/property-access": "^3.2",
"symfony/swiftmailer-bundle": "^2.3",
"symfony/symfony": "^3.2",
"twig/extensions": "^1.3",
"twig/twig": "^1.28",
"white-october/pagerfanta-bundle": "^1.0"
},
"require-dev": {
"friendsofphp/php-cs-fixer" : "^1.12",
"phpunit/phpunit" : "^4.8 || ^5.0",
"sensio/generator-bundle" : "^3.0",
"symfony/phpunit-bridge" : "^3.0"
},
详情
我正在使用翻译包.所以在我的表单中,对于每个字段,我都有两种语言的字段.表单完美呈现多语言选项.但是当我提交表单时,出现以下错误:
I am using translation bundle. So in my form, for each field I am having that fields for two languages. The form is rendering with multi-language options perfectly. But when I submits the form, I am getting below error:
无法确定属性translations"的访问类型.
Could not determine access type for property "translations".
vendor\symfony\symfony\src\Symfony\Component\PropertyAccess\PropertyAccessor.php
中第 649 行的堆栈跟踪
Stack Trace in vendor\symfony\symfony\src\Symfony\Component\PropertyAccess\PropertyAccessor.php
at line 649
} elseif (self::ACCESS_TYPE_MAGIC === $access[self::ACCESS_TYPE]) {
$object->{$access[self::ACCESS_NAME]}($value);
} elseif (self::ACCESS_TYPE_NOT_FOUND === $access[self::ACCESS_TYPE]) {
throw new NoSuchPropertyException(sprintf('Could not determine access type for property "%s".', $property));
} else {
throw new NoSuchPropertyException($access[self::ACCESS_NAME]);
}
环境
奏鸣曲包
$ composer show sonata-project/*
sonata-project/admin-bundle 3.12.0 The missing Symfony Admin ...
sonata-project/block-bundle 3.3.0 Symfony SonataBlockBundle
sonata-project/cache 1.0.7 Cache library
sonata-project/core-bundle 3.2.0 Symfony SonataCoreBundle
sonata-project/doctrine-orm-admin-bundle 3.1.3 Symfony Sonata / Integrate...
sonata-project/exporter 1.7.0 Lightweight Exporter library
sonata-project/translation-bundle 2.1.0 SonataTranslationBundle
Symfony 软件包
Symfony packages
$ composer show symfony/*
symfony/monolog-bundle 3.0.1 Symfony MonologBundle
symfony/phpunit-bridge v3.2.1 Symfony PHPUnit Bridge
symfony/polyfill-apcu v1.3.0 Symfony polyfill backporting apcu_* func...
symfony/polyfill-intl-icu v1.3.0 Symfony polyfill for intl's ICU-related ...
symfony/polyfill-mbstring v1.3.0 Symfony polyfill for the Mbstring extension
symfony/polyfill-php56 v1.3.0 Symfony polyfill backporting some PHP 5....
symfony/polyfill-php70 v1.3.0 Symfony polyfill backporting some PHP 7....
symfony/polyfill-util v1.3.0 Symfony utilities for portability of PHP...
symfony/security-acl v3.0.0 Symfony Security Component - ACL (Access...
symfony/swiftmailer-bundle v2.4.2 Symfony SwiftmailerBundle
symfony/symfony v3.2.2 The Symfony PHP framework
PHP 版本
$ php -v
# $ php -v
PHP 5.6.20 (cli) (built: Mar 31 2016 14:56:44)
Copyright (c) 1997-2016 The PHP Group
Zend Engine v2.6.0, Copyright (c) 1998-2016 Zend Technologies
推荐答案
大多数情况下,当您忘记在实体类的构造函数中初始化集合时,会抛出此错误.
Most of the time this error gets thrown when you forget to initialize a collection in the constructor of your entity class.
看看你的实体类.您需要添加
Look at your entity class. You need to add
$this->translations = new ArrayCollection();
到构造函数.
更一般地说,PropertyAccess 负责调用实体的 setter/getter,因此通常是与实体类相关的问题,而不是与表单类型相关的问题.
More generally, PropertyAccess is responsible for calling the setters/getters of your entity so usually it is a problem related to your entity class and not your form type.
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