使用 EntityType 构建选择时,如何在 Twig 中设置值? [英] How can I set a value in Twig when the select is built using EntityType?
问题描述
在表单中说我有一个像这样的构建器选项:
In a Form say I have a builder option like this:
->add('choice', ChoiceType::class, [
'choices' => [
'Cheese' => 'cheese',
'Plain' => 'plain
]
])
假设我们正在编辑这个选项,在数据库中他们已经选择了plain.使用 Twig,我们可以像这样编写小部件:
And let's say we are editing this option, in the database they've already selected plain. With twig we can write the widget like this:
{{ form_widget(BurgerForm.choice, {
'value': burger.type
}) }}
这将使数据库中的值成为选择的预选值.但是如果你对 EntityType 做同样的事情:
This will make the value in the database the pre-selected value for the select. But if you do the same thing with EntityType:
->add('choice', EntityType::class, [
'class' => 'AppBundle:BurgersTypes',
'choice_label' => 'type'
])
并且您使用相同的树枝,它不会从数据库中预先选择该选项.如何从数据库中获取值以显示为小部件的预选值?
And you use the same twig it doesn't pre-select the option from the database. How can I get the value from the database to show as the pre-selected value of the widget?
推荐答案
为此表单预先选择一个值意味着在基础数据上设置一个值.在你的情况下,控制器应该看起来像:
Pre-selecting a value for this form means setting a value on the underlying data. In your case, the controller ought to look something like:
// src/AppBundle/Controller/MyController.php
namespace AppBundle\Controller\MyController;
use AppBundle\Entity\Order;
use AppBundle\Entity\BurgersTypes;
use AppBundle\Form\Type\FormType;
use Symfony\Component\HttpFoundation\Request;
public function formAction(Request $request)
{
$obj = new Order();
$defaultBurgerChoice = new BurgersTypes('cheese');
$ob->setChoice($defaultBurgerChoice);
$form = $this->create(FormType::class, $obj);
$form->handleRequest($request);
...
// Now, if the form needs to render a value for `choice`,
// it will have the value of BurgerForm.choice determined
// intentionally - by your default, or overridden and
// handled in the request!
return [
'BurgerForm' => $form->createView()
]
}
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