字符复制到字符数组 [英] copy char to char array

问题描述

我想一个串复制到C字符串数组：

I am trying to copy a "string" to array of strings in C:

const gchar  *strAuth, *strEditor, *strTitle; 
gchar *strings[18][150];
strcpy(strings[0],strAuth);

在编译时，GCC是给予警告：
警告：传递从兼容的指针类型'的strcpy'的参数1 [默认启用]

while compiling, gcc is giving warning: warning: passing argument 1 of ‘strcpy’ from incompatible pointer type [enabled by default]

可能的话，由于该故障矿，在code的后期

Possibly, due to this fault of mine, the check and print in the later part of the code

  g_print("%s", strings[0]);
  int i=0;
  while (i <= 18) {
    if (strlen(strings[i]) != 0) {
      g_string_append_printf(tstring, "\t%s=\"%s\",\n",
      keyword[i], strings[i]);
      i++;
    } 
  }

也没有工作（它是印刷空字符串为好）。
C是不是我的语言，所以好心帮

is also not working (it is printing empty strings as well). C is not my language, so kindly help

注：thecked 这并的这个，但未能帮助自己
注意：gchar对应的标准C char类型。在巧舌如簧

NB:thecked this and this, but failed to help myself NB: gchar "Corresponds to the standard C char type." in glib

推荐答案

最直接的修复（不建议一个完全不同的方法）需要一对夫妇的修正。

The most immediate fix (without suggesting a totally different approach) requires a couple of fixes.

有关警告的事情是，你正在创建的18x150指针数组，但我猜你要18串长度150，这样的定义应该是：

The thing about the warning is that you are creating an array of 18x150 pointers, but I guess you want 18 strings of length 150, so the definition should be:

gchar strings[18][150];  // 18 strings of 150 chars

您code的样子，你可能还假定为零初始化（空字符串，如果不填写），所以你可以添加：

The way your code looks, you would probably also assume to be zero initialized (empty strings if not filled) so you might add:

gchar strings[18][150]= { "", };  // 18 empty strings of 150 chars

在code另一个（更严重的）错误是你的循环运行[0 ... 18]。但是，你的字符串列表仅 gchar *串[18] [150]; 所以它应该运行[0..17]。同时也应该发生的我递增时长字符串[我]是零（否则你将得到一个无限循环，从来没有达到结束，如果一个字符串为空）。

Another (more severe) error in your code is that your loop is running [0...18]. But your list of strings is only gchar *strings[18][150]; so it should run [0..17]. Also the increment of I should also happen when length strings[i] is zero (otherwise you will get an infinite loop, never reaching the end if one string is empty).

  while (i < 18) {  // <-- FIX 
    if (strlen(strings[i]) != 0) {
      g_string_append_printf(tstring, "\t%s=\"%s\",\n",
      keyword[i], strings[i]);
    } 
    i++;  // <-- FIX 
  }

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