从没有完全填补字符数组的字符串 [英] String from not fully filled character array

问题描述

以下code，很明显，给人一种相当怪异的结果。

 的char []数据=新的char [5];
数据[0] ='A';
数据[1] ='B';
数据[2] ='c'的;通过out.println（'+新的String（数据）+'）;
 

  

ABC□□

有没有一种方法来创建一个字符数组，考虑到整个阵列可能不填充与字符结尾的字符串？

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原因问题：使用的 Reader.read（的char []） 方法，你给它一个字符数组来填充，这我只能假设不会被填满，除非你是幸运的，当你到达流的末尾。所以，想知道你怎么可以变成一个字符串，这个你可以追加到的StringBuffer 。现在意识到，虽然该读方法实际上返回的字节数读虽然，我以为可以结合使用的StringBuffer.append（的char [ ]，INT，INT），这使得我的问题没有实际意义。但是，仍然是我很好奇，这也不是我设法使用Google找到，所以我想这个问题是好事，有一个答案在这里;）

解决方案

的字符串具有构造<一个href=\"http://docs.oracle.com/javase/6/docs/api/java/lang/String.html#String%28char%5b%5d,%20int,%20int%29\"相对=nofollow>字符串（的char []的价值，诠释抵消，诠释计数）接受字符加长度（和偏移）：

 一个String =新的String（数据，0，3）;
 

假设没有嵌入空字符（其中一个领先的空字符被认为是一个嵌入的NULL）的数据的解决方案将需要找到第一个空字符确定字符在数据号：

  INT长度= 0;
而（长度LT; data.length＆放大器;＆安培;！0 =数据[长度]）长度++;
字符串s =新的String（数据，0，长度）;
 

The following code, obviously, gives a rather weird result.

char[] data = new char[5];
data[0] = 'a';
data[1] = 'b';
data[2] = 'c';

out.println("'" + new String(data) + "'");

'abc□□'

Is there a way to create a string from a character array which takes into account that the whole array might not be filled to the end with characters?

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Reason for question: When using the Reader.read(char[]) method you give it a character array to fill, which I can only assume won't be fully filled, unless you're lucky, when you reach the end of the stream. So was wondering how you could turn this into a string you could append to a StringBuffer. Realize now though that the read method actually returns the number of bytes read though, which I assume can be used in combination with StringBuffer.append(char[], int, int), which renders my question moot. But, still something I am curious about and not something I managed to find by googling, so I guess this question is good to have an answer for here ;)

解决方案

The String has constructorString(char[] value, int offset, int count) that accepts an array of char plus length (and offset):

String s = new String(data, 0, 3);

Assuming no embedded null characters (where a leading null character is considered to be an embedded null) in data the solution would need to locate the first null character to determine the number of char in data:

int length = 0;
while (length < data.length && 0 != data[length]) length++;
String s = new String(data, 0, length);

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