将指向任何成员函数的指针作为类模板参数传递 [英] Passing pointer to any member function as class template argument

问题描述

template<typename T, typename M, M Method>
class ProxyObject
{
public:

    template<typename... Args>
    void Invoke (T& Object, _In_ Args&&... A)
    {
        (void)(Object.*Method)(std::forward<Args>(A)...);
    }
};

class Object
{
public:

    int MyMethod (int Val)
    {
        wcout << L"Hello!" << endl;
        return Val;
    }
};


int wmain ()
{
    Object myObj;
    ProxyObject<Object, decltype(&Object::MyMethod), &Object::MyMethod> obj;

    obj.Invoke(myObj, 10);

    return 0;
}

decltype(&Object::MyMethod) 在 obj 的定义中似乎是多余的.有什么办法可以让 ProxyObject 自动推断传递的成员函数指针的类型，这样我就可以定义 obj 如下:

The decltype(&Object::MyMethod) seems redundant in the definition of obj. Is there any way to make the ProxyObject automatically infer the type of the pointer-to-member-function being passed, so that I can define obj as follows:

ProxyObject<Object, &Object::MyMethod> obj;

推荐答案

我认为类模板是不可能的，因为你必须明确指定成员函数类型.

I think it's impossible for class template, because you have to specify the member function type explicitly.

模板函数可以帮助您进行参数推导:

Template function could help you lot with the argument deduction:

template<typename T, typename M, typename... Args>
void invoke (T& Object, M Method, Args&&... A)
{
    (void)(Object.*Method)(std::forward<Args>(A)...);
}

然后

invoke(myObj, &Object::MyMethod, 10);

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