故障传递结构的数组 [英] Trouble passing an array of structs

问题描述

我不能为我的生活弄清楚如何通过我的整个程序数组结构的。任何人都可以伸出援助之手？现在，我得到的主要错误，上面写着：预计前原前pression'）'令牌。

标题：

 的#ifndef HEADER_H_INCLUDED
＃定义HEADER_H_INCLUDED＃包括LT＆;＆iostream的GT;
＃包括LT＆;＆的fstream GT;
＃包括LT＆;串GT;
＃包括LT＆; CString的GT;
＃包括LT＆;＆了iomanip GT;
＃包括LT＆;＆cctype GT;使用命名空间std;地址类型结构
{
    焦炭streetName [36];
    焦炭的cityName [21];
    焦状态[3];
    焦炭拉链code [6];
    炭phoneNumber的[15];
};结构contactType
{
    焦炭CONTACTNAME [31];
    焦炭生日[11];
    地址类型AddressInfo的;
    串typeOfentry;
};typedef结构contactType CONTACTINFO;无效的extern READFILE（ifstream的＆安培;，＆INT放大器;，结构contactType * arrayOfStructs）;
无效的extern sortAlphabetically（）;
无效的extern userInput（字符和放大器;）;
无效的extern输出（焦＆安培;）;#ENDIF // HEADER_H_INCLUDED
 

主：

 的#includeheader.h诠释的main（）
{
    ifstream的INFILE;
    焦炭反应;
    INT listLength;
    结构arrayOfStructs;    inFile.open（AddressBook.txt）;    如果（！INFILE）
    {
        COUT＆LT;＆LT; 无法打开输入文件。
             ＆LT;＆LT; ENDL;
            返回1;
    }    READFILE（INFILE，listLength，arrayOfStructs）;
    sortAlphabetically（）;
    userInput（响应）;
    输出（响应）;    返回0;
}
 

READFILE：

 的#includeheader.h无效READFILE（ifstream的＆安培; INFILE，INT和放大器; listLength，结构arrayOfStructs []）
{
    CONTACTINFO arrayOfStructs [listLength]
    焦炭丢弃;    INFILE＆GT;＆GT; listLength;
    inFile.get（丢弃）;    的for（int i = 0; I＆LT; listLength;我++）
    {
        inFile.get（arrayOfStructs [I] .contactName，30）;
        inFile.get（丢弃）;
        inFile.get（arrayOfStructs [I] .birthday，11）;
        inFile.get（丢弃）;
        inFile.get（arrayOfStructs [I] .addressInfo.streetName，36）;
        inFile.get（丢弃）;
        inFile.get（arrayOfStructs [I] .addressInfo.cityName，21）;
        inFile.get（丢弃）;
        inFile.get（arrayOfStructs [Ⅰ] .addressInfo.state，3）;
        inFile.get（丢弃）;
        inFile.get（arrayOfStructs [I] .addressInfo.zip code，6）;
        inFile.get（丢弃）;
        inFile.get（arrayOfStructs [I] .addressInfo.phoneNumber，15）;
        inFile.get（丢弃）;
        INFILE＆GT;＆GT; arrayOfStructs [I] .typeOfentry;
        inFile.get（丢弃）;
    }
}
 

解决方案

您有：

 结构arrayOfStructs;
 

您需要：

 结构contactType arrayOfStructs [200]; //假设你要200结构
 

I cant for the life of me figure out how to pass this array of structs throughout my program. Could anyone lend a hand? Right now i am getting an error in main that says: expected primary expression before ')' token.

Header:

#ifndef HEADER_H_INCLUDED
#define HEADER_H_INCLUDED

#include <iostream>
#include <fstream>
#include <string>
#include  <cstring>
#include <iomanip>
#include <cctype>

using namespace std;

struct addressType
{
    char streetName[36];
    char cityName[21];
    char state[3];
    char zipcode[6];
    char phoneNumber[15];
};

struct contactType
{
    char contactName[31];
    char birthday[11];
    addressType addressInfo;
    string typeOfentry;
};

typedef struct contactType contactInfo;

void extern readFile(ifstream&, int&, struct contactType *arrayOfStructs);
void extern sortAlphabetically();
void extern userInput(char&);
void extern output(char&);



#endif // HEADER_H_INCLUDED

main:

#include "header.h"

int main()
{
    ifstream inFile;
    char response;
    int listLength;
    struct arrayOfStructs;

    inFile.open("AddressBook.txt");

    if (!inFile)
    {
        cout << "Cannot open the input file."
             << endl;
            return 1;
    }

    readFile(inFile, listLength, arrayOfStructs);
    sortAlphabetically();
    userInput(response);
    output(response);

    return 0;
}

readFile:

#include "header.h"

void readFile(ifstream& inFile, int& listLength, struct arrayOfStructs[])
{
    contactInfo arrayOfStructs[listLength];
    char discard;

    inFile >> listLength;
    inFile.get(discard);

    for (int i = 0; i < listLength; i++)
    {
        inFile.get(arrayOfStructs[i].contactName, 30);
        inFile.get(discard);
        inFile.get(arrayOfStructs[i].birthday, 11);
        inFile.get(discard);
        inFile.get(arrayOfStructs[i].addressInfo.streetName, 36);
        inFile.get(discard);
        inFile.get(arrayOfStructs[i].addressInfo.cityName, 21);
        inFile.get(discard);
        inFile.get(arrayOfStructs[i].addressInfo.state, 3);
        inFile.get(discard);
        inFile.get(arrayOfStructs[i].addressInfo.zipcode, 6);
        inFile.get(discard);
        inFile.get(arrayOfStructs[i].addressInfo.phoneNumber, 15);
        inFile.get(discard);
        inFile >> arrayOfStructs[i].typeOfentry;
        inFile.get(discard);
    }
}

解决方案

Where you have:

struct arrayOfStructs;

You need:

struct contactType arrayOfStructs[200]; // assuming you want 200 structs 

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