Lodash：获取新的阵列，在多张比赛JSON [英] Lodash:Getting new array with mulitple matches in JSON

问题描述

我有一个嵌套的JSON这个样子的。

I have a nested JSON look like this

[
{arrivalTime: "10:30 PM"
 availableSeats: 23
boardingPoints: [{id: "3882"
location: "abc"
time: "02:30PM"},{id: "3882"
location: "xyz"
time: "02:30PM"}]
busType: "Scania Metrolink"
commPCT: 8
departureTime: "1:15 PM"
droppingPoints: null
},
{arrivalTime: "10:30 PM"
 availableSeats: 23
boardingPoints: [{id: "3882"
location: "def"
time: "02:30PM"},{id: "3882"
location: "jkl"
time: "02:30PM"}]
busType: "Scania "
commPCT: 8
departureTime: "1:15 PM"
droppingPoints: null
}    
]

在此我希望得到一个condtion匹配新的数组。
下面是它

From this i want to get new array that matches a condtion. Here is it

1.get在指定只有用户位置新阵列 boardingPoints 对象。

1.get the new array with only the user specified location in boardingPoints object.

例如-A：假设位置值为 XYZ 将只返回用JSON
 包含位置 XYZ 仅在 boardingPoints 对象。

eg-a:Suppose the location value is xyz it will return only the JSON with that contains the location xyz only in the boardingPoints object.

输出

的 {arrivalTime：10:30 PM
 availableSeats：23
boardingPoints：[{ID：3882
位置：ABC
时间：下午2点30}，{ID：3882
位置： XYZ
时间：下午2点30}]
busType：斯堪尼亚林克
commPCT：8
departureTime：下午1:15
droppingPoints：空
} 的

例如-B：假设位置值为 XYZ 和 DEF 它应该只使用JSON返回包含上述两个位置仅在 boardingPoints 对象。

eg-b:Suppose location value is xyz and def it should returns only with JSON that contains the above two locations only in the boardingPoints object.

输出

的 {arrivalTime：10:30 PM
 availableSeats：23
boardingPoints：[{ID：3882
位置：ABC
时间：下午2点30}，{ID：3882
位置： XYZ
时间：下午2点30}]
busType：斯堪尼亚林克
commPCT：8
departureTime：下午1:15
droppingPoints：空
}，
{arrivalTime：10:30 PM
 availableSeats：23
boardingPoints：[{ID：3882
位置： DEF
时间：下午2点30}，{ID：3882
位置：JKL
时间：下午2点30}]
busType：斯堪尼亚
commPCT：8
departureTime：下午1:15
droppingPoints：空
} 的

我知道这可能使用实施 lodash ，但我不知道该怎么做。

I know this may be implemented using lodash but i don't know how to do it

目前我知道的只有 lodash 的比赛，但我不知道我可以在我的情况下，使用此功能。

Currently i know about only matches in lodash but i don't know how can i use this in my case.

    var users = [
      { 'user': 'barney', 'age': 36, 'active': true },
      { 'user': 'fred',   'age': 40, 'active': false }
    ];  
    _.filter(users, _.matches({ 'age': 40}));
// → [{ 'user': 'fred', 'age': 40, 'active': false }]

是否有可能在JavaScript中的本地方法？

Is it possible with native method in javascript?

推荐答案

您可以使用一系列lodash的一些逻辑来得到预期的结果调用。事情是这样的：

You can use a series of lodash calls with some logic to get the expected results. Something like this:

var _ = require('lodash');

var result = [
    {
        arrivalTime: "10:30 PM",
        availableSeats: 23,
        boardingPoints: [{
            id: "3882",
            location: "abc",
            time: "02:30PM"
        },{
            id: "3882",
            location: "xyz",
            time: "02:30PM"
        }],
        busType: "Scania Metrolink",
        commPCT: 8,
        departureTime: "1:15 PM",
        droppingPoints: null,
    },
    {
        arrivalTime: "10:30 PM",
        availableSeats: 23,
        boardingPoints: [{
            id: "3882",
            location: "def",
            time: "02:30PM"
        },{
            id: "3882",
            location: "jkl",
            time: "02:30PM"
        }],
        busType: "Scania ",
        commPCT: 8,
        departureTime: "1:15 PM",
        droppingPoints: null
    }
];
var locations = ['xyz'];

var f = _.filter(result, function(obj) {
    var value = _.map(obj.boardingPoints, 'location');       
    var i, len;

    for (i = 0, len = locations.length; i < len; i++) {
        if (_.indexOf(value, locations[i]) >= 0) {
            return true;
        }
    }
    return false;
});

console.log(f);  // result is your eg-a

在

locations = ['xyz', 'def'];

的结果将是您如-B

the result will be your eg-b

到解决方案另一种方法是用连锁交叉口（）的调用：

var f = _.filter(result, function(obj) {
  return _.chain(obj.boardingPoints).map('location').intersection(locations).value().length > 0;
});

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