如何在特定位置之前/之后从文本文件中读取输入 [C++]? [英] How to read input from the text file until/after a specific location [C++]?

问题描述

在我的项目中，我需要从文本文件中获取有关电路的数据，然后我需要解析它并生成输出数据.这是文本文件的示例数据

In my Project I need to get data about circuit from a text file then I need to parse it and produce to output data. Here is a sample data for the text file

AND1 Adder1-3 Adder1-4//表示 AND1 门从Adder1 的第 3 个输出和 Adder1 的第 4 个输出的第二个输入

AND1 Adder1-3 Adder1-4 // Means AND1 gate gets its first input from Adder1's 3rd output and its second input from Adder1's 4th output

AND2 Adder1-4 Adder1-2

AND2 Adder1-4 Adder1-2

OR1 AND1-1 AND2-1//OR1的两个输入来自AND1的第一个输出和AND2的第一个输出

OR1 AND1-1 AND2-1 //OR1's two inputs are from AND1's 1st output and AND2's 1st output

现在我需要先读取组件名称，这很容易:

now I need to read the component name first which is easy:

infile>>componentName;

但是对于第二部分，我认为我可以通过多种方式进行

But for the second part I though I could to this in to ways

1. 读取整个数据并将其分成两部分: ComponentName -输出.
2. 读取直到-"并将其放入字符串变量然后读取在-"之后并将其放入整数变量并对所有重复此操作线.

我尝试了第一种方法，但我真的坚持将字符串转换为整数(我尝试使用 stoi 但它仅用于 C++ :( 并且还遇到了几个问题)但我虽然第二种方法会更容易，但我不能不知道该怎么做.

I tried the first way but I really stuck at converting string into integer (I tried using stoi but its for C++ only :( and also encountered with couple of problems) but I though the second way would be much easier but I couldn't figure it how to do it.

你能帮我解决这个问题吗?基本上我需要将组件名称(在-"之前)放入字符串变量并将整数(在-"之后)放入整数变量.

So can you help me with this ? Basicly I need to put component name(before "-") into string variable and put the integer (after "-") into integer variable.

注意:对不起，我的英语不好，不是母语人士.由于项目很大，我没有在上面放不必要的代码.

NOTE: Sorry for my poor English not a Native Speaker. and since the Project is large I didn't put unnecessary codes above.

推荐答案

这是相当基本的，但应该可以帮助您入门.对于这些任务，我更喜欢 scanf 系列.

This is rather basic, but should get you started. I prefer the scanf family for these tasks.

#include <stdio.h>
#include <iostream>

using namespace std;
int main() {
FILE *fp=fopen("tmpfile", "r");
char oper[5], dev1[10], dev2[10];
int op1, op2;
fscanf(fp, "%s %[^-]-%d %[^-]-%d", oper, dev1, &op1, dev2, &op2);
cout<<oper<<endl;
cout<<dev1<<endl;
cout<<op1<<endl;
cout<<dev1<<endl;
cout<<op2<<endl;
fclose(fp);

}

为 AND2 Adder1-4 Adder1-2 产生的输出:

AND2
Adder1
4
Adder1
2

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