LoDash挑战,我有我需要过滤对象的数组,对值数组 [英] LoDash challenges, I have an array of objects I need to filter, for an array of values
问题描述
我有我需要通过 _id
使用 _id
值数组来过滤以下对象数组。
VAR对象= {[
_account:YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo
_id:055z5gzVyVfzlBnEOqYvcoLL1ZgOWJhkrWMkv2
},{
_account:YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo
_id:LvvrvyrOGOS2e5yE0Bdki45Y1ndVlgfoZ2zoOp
},{
_account:mjj9jp92z2fD1mLlpQYZI1gAd4q4LwTKmBNLz
_id:rEEwENwnznCQvkm61wRziKlMRPqaYztnR4vn61
},{
_account:AaaraZrLqLfzRYoAPlb6ujPELWVW4dTK4eJWj
_id:944r40rPgPU2nXqzMYolS5nyo6Eo9OuqrlDkB
},{
_account:AaaraZrLqLfzRYoAPlb6ujPELWVW4dTK4eJWj
_id:rEEwENwnznCQvkm61wZ9uey62Pjy5YTqgYGDK
}];VAR id_values = [
rEEwENwnznCQvkm61wZ9uey62Pjy5YTqgYGDK
944r40rPgPU2nXqzMYolS5nyo6Eo9OuqrlDkB
rEEwENwnznCQvkm61wRziKlMRPqaYztnR4vn61
];
我相信区别
,拉
或无
可能是有用的,但我不能从LoDash文档区分它们。我也觉得的forEach
, forIn
或 uniq的
可能是有用的。我能够过滤的对象之一了使用拒绝
:
_。拒绝(对象,{
_id:rEEwENwnznCQvkm61wZ9uey62Pjy5YTqgYGDK
});
不过这并不能帮助我需要通过一个数组进行筛选。结果应该是以下数组:
VAR的结果= [{
_account:YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo
_id:055z5gzVyVfzlBnEOqYvcoLL1ZgOWJhkrWMkv2
},{
_account:YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo
_id:LvvrvyrOGOS2e5yE0Bdki45Y1ndVlgfoZ2zoOp
}];
这是我知道如何使用LoDash做最快的方式:
VAR对象= {[\r
_account:YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo\r
_id:055z5gzVyVfzlBnEOqYvcoLL1ZgOWJhkrWMkv2\r
},{\r
_account:YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo\r
_id:LvvrvyrOGOS2e5yE0Bdki45Y1ndVlgfoZ2zoOp\r
},{\r
_account:mjj9jp92z2fD1mLlpQYZI1gAd4q4LwTKmBNLz\r
_id:rEEwENwnznCQvkm61wRziKlMRPqaYztnR4vn61\r
},{\r
_account:AaaraZrLqLfzRYoAPlb6ujPELWVW4dTK4eJWj\r
_id:944r40rPgPU2nXqzMYolS5nyo6Eo9OuqrlDkB\r
},{\r
_account:AaaraZrLqLfzRYoAPlb6ujPELWVW4dTK4eJWj\r
_id:rEEwENwnznCQvkm61wZ9uey62Pjy5YTqgYGDK\r
}];\r
\r
VAR id_values = [\r
rEEwENwnznCQvkm61wZ9uey62Pjy5YTqgYGDK\r
944r40rPgPU2nXqzMYolS5nyo6Eo9OuqrlDkB\r
rEEwENwnznCQvkm61wRziKlMRPqaYztnR4vn61\r
];\r
\r
VAR指数= index_of_array(id_values);\r
\r
VAR的结果= _.reject(对象,函数(对象){\r
回报指数[object._id] ||假;\r
});\r
\r
的console.log(结果);
\r
&LT;脚本SRC =http://cdn.jsdelivr.net/lodash /2.1.0/lodash.compat.js\"></script>\r
\r
&LT;脚本&GT;\r
/ *\r
创建键阵列的索引。允许您检查数组是否\r
在O(1)时间特定的键(相对于o使用的indexOf(n)的时间)。它\r
需要O(n)的时间来创建其中n是阵列的长度的索引。\r
\r
例如\r
\r
变种键= [1,2,3];\r
VAR指数= index_of_array(键); // 准时\r
的console.log(指数[1] ||假); //真 - O(1)时间\r
的console.log(指数[4] ||假); //假 - O(1)时间\r
的console.log(keys.indexOf(1)&GT = 0); //真 - O(n)的时间\r
的console.log(keys.indexOf(4)&GT = 0); //假 - O(n)的时间\r
* /\r
\r
功能index_of_array(阵列){\r
VAR长度= array.length\r
,结果= {}\r
,索引= 0;\r
\r
而(指数&LT;长度)\r
结果[数组[索引++] = TRUE;\r
返回结果;\r
}\r
&LT; / SCRIPT&GT;
\r
希望有所帮助。
I have the following array of objects that I need to filter by _id
using an array of _id
values.
var objects = [{
_account: "YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo",
_id: "055z5gzVyVfzlBnEOqYvcoLL1ZgOWJhkrWMkv2"
}, {
_account: "YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo",
_id: "LvvrvyrOGOS2e5yE0Bdki45Y1ndVlgfoZ2zoOp"
}, {
_account: "mjj9jp92z2fD1mLlpQYZI1gAd4q4LwTKmBNLz",
_id: "rEEwENwnznCQvkm61wRziKlMRPqaYztnR4vn61"
}, {
_account: "AaaraZrLqLfzRYoAPlb6ujPELWVW4dTK4eJWj",
_id: "944r40rPgPU2nXqzMYolS5nyo6Eo9OuqrlDkB"
}, {
_account: "AaaraZrLqLfzRYoAPlb6ujPELWVW4dTK4eJWj",
_id: "rEEwENwnznCQvkm61wZ9uey62Pjy5YTqgYGDK"
}];
var id_values = [
"rEEwENwnznCQvkm61wZ9uey62Pjy5YTqgYGDK",
"944r40rPgPU2nXqzMYolS5nyo6Eo9OuqrlDkB",
"rEEwENwnznCQvkm61wRziKlMRPqaYztnR4vn61"
];
I believe that difference
, pull
or without
could be useful but I can't tell them apart from the documentation on LoDash. I also think forEach
, forIn
or uniq
could be useful. I was able to filter one of the objects out using reject
:
_.reject(objects, {
_id: "rEEwENwnznCQvkm61wZ9uey62Pjy5YTqgYGDK"
});
Still this does not help me with the need to filter by an array. The result should be the following array:
var result = [{
_account: "YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo",
_id: "055z5gzVyVfzlBnEOqYvcoLL1ZgOWJhkrWMkv2"
}, {
_account: "YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo",
_id: "LvvrvyrOGOS2e5yE0Bdki45Y1ndVlgfoZ2zoOp"
}];
This is the fastest way I know how to do it using LoDash:
var objects = [{
_account: "YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo",
_id: "055z5gzVyVfzlBnEOqYvcoLL1ZgOWJhkrWMkv2"
}, {
_account: "YzzrzBrO9OSzo6BXwAvVuL5dmMKMqkhOoEqeo",
_id: "LvvrvyrOGOS2e5yE0Bdki45Y1ndVlgfoZ2zoOp"
}, {
_account: "mjj9jp92z2fD1mLlpQYZI1gAd4q4LwTKmBNLz",
_id: "rEEwENwnznCQvkm61wRziKlMRPqaYztnR4vn61"
}, {
_account: "AaaraZrLqLfzRYoAPlb6ujPELWVW4dTK4eJWj",
_id: "944r40rPgPU2nXqzMYolS5nyo6Eo9OuqrlDkB"
}, {
_account: "AaaraZrLqLfzRYoAPlb6ujPELWVW4dTK4eJWj",
_id: "rEEwENwnznCQvkm61wZ9uey62Pjy5YTqgYGDK"
}];
var id_values = [
"rEEwENwnznCQvkm61wZ9uey62Pjy5YTqgYGDK",
"944r40rPgPU2nXqzMYolS5nyo6Eo9OuqrlDkB",
"rEEwENwnznCQvkm61wRziKlMRPqaYztnR4vn61"
];
var index = index_of_array(id_values);
var result = _.reject(objects, function (object) {
return index[object._id] || false;
});
console.log(result);
<script src="http://cdn.jsdelivr.net/lodash/2.1.0/lodash.compat.js"></script>
<script>
/*
Creates an index of an array of keys. Allows you to check whether the array
has a specific key in O(1) time (as compared to O(n) time using indexOf). It
takes O(n) time to create the index where n is the length of the array.
e.g.
var keys = [1,2,3];
var index = index_of_array(keys); // O(n) time
console.log(index[1] || false); // true - O(1) time
console.log(index[4] || false); // false - O(1) time
console.log(keys.indexOf(1) >= 0); // true - O(n) time
console.log(keys.indexOf(4) >= 0); // false - O(n) time
*/
function index_of_array(array) {
var length = array.length
, result = {}
, index = 0;
while (index < length)
result[array[index++]] = true;
return result;
}
</script>
Hope that helps.
这篇关于LoDash挑战,我有我需要过滤对象的数组,对值数组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!