Tic Tac Toe 对角线检查 [英] Tic Tac Toe diagonal check

问题描述

我正在构建一个井字游戏，我有一个如下所示的垂直和水平检查:

I'm building a game of Tic-Tac-Toe, and I have a vertical and horizontal check that look like this:

def check_win_left_vert (board):
    win = True
    x = 0
    for y in range (2):
        if board[y][x] != board[y+1][x]:
            win = False
    return win

它通过增加 y 轴来看板；我对 x 轴使用相同的方法.我将如何为对角轴执行此操作?我会增加两者吗?

It looks through the board by incrementing the y axis; I use the same method for the x axis. How would I do this for a diagonal axis? Would I increment both?

推荐答案

所有带有列表推导式的检查

game_board = [ [1, 0, 1],
               [0, 1, 0],
               [0, 1, 0] ]

# Horizontals
h = [str(i+1) + ' Row' for i, v in enumerate(game_board) if sum(v) == 3]

# Verticals
v = [str(i+1) + ' Col' for i in range(3) if sum([j[i] for j in game_board]) == 3]

# Diagonals
d = [['Left Diag', '','Right Diag'][i+1] for i in [-1, 1] if sum([game_board[0][1+i], game_board[1][1]], game_board[2][1-i]) == 3]

if any([h,v,d]):
    print('You won on:', h, v, d)
else:
    print('No win yet')

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