如何pivot_wider 并通过复制值来填充缺失值 [英] How to pivot_wider and fill in missing values by duplicating values

查看:32
本文介绍了如何pivot_wider 并通过复制值来填充缺失值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试从长格式到宽格式获取数据框,但由于其结构,每当我使用 pivot_wider() 时,我都会得到两列包含数据向量的列.

I am trying to get a data frame from a long to a wide format, but due to its structure, whenever I use pivot_wider() I get two columns that contain vectors of data.

这是原始数据:

structure(list(type = c("radio", "radio", "radio", "television", 
"television", "television", "television", "television", "television", 
"television", "television", "television", "television", "television", 
"television", "television", "television", "television", "television"
), Resource = c("samsung", "samsung", "samsung", "samsung", "samsung", 
"samsung", "samsung", "samsung", "samsung", "samsung", "samsung", 
"sony", "sony", "sony", "sony", "sony", "sony", "sony", "sony"
), Property = c("lot_number", "lot_number", "manufacturer", "lot_number", 
"lot_number", "lot_number", "lot_number", "lot_number", "manufacturer", 
"other_PN", "part_number", "lot_number", "lot_number", "lot_number", 
"lot_number", "lot_number", "manufacturer", "other_PN", "part_number"
), value = c("12345", "54321", "John", "9876", "12345", "54321", 
"56789", "67890", "Walt", "5g6h3f", "6789", "9876", "12345", 
"54321", "56789", "67890", "John", "2a3b4c", "3461")), class = c("spec_tbl_df", 
"tbl_df", "tbl", "data.frame"), row.names = c(NA, -19L), spec = structure(list(
    cols = list(type = structure(list(), class = c("collector_character", 
    "collector")), Resource = structure(list(), class = c("collector_character", 
    "collector")), Property = structure(list(), class = c("collector_character", 
    "collector")), value = structure(list(), class = c("collector_character", 
    "collector"))), default = structure(list(), class = c("collector_guess", 
    "collector")), skip = 1), class = "col_spec"))

我使用的命令:

df_wide <- df %>% pivot_wider(names_from = Property, values_from = value)

但是多个值被保存为lot_number"中的一个向量.列:

but multiple values are saved as a vector in the "lot_number" column:

structure(list(type = c("radio", "television", "television"), 
    Resource = c("samsung", "samsung", "sony"), lot_number = list(
        c("12345", "54321"), c("9876", "12345", "54321", "56789", 
        "67890"), c("9876", "12345", "54321", "56789", "67890"
        )), manufacturer = list("John", "Walt", "John"), other_PN = list(
        NULL, "5g6h3f", "2a3b4c"), part_number = list(NULL, "6789", 
        "3461")), row.names = c(NA, -3L), class = c("tbl_df", 
"tbl", "data.frame"))

这是我最后想要得到的数据框.请注意,在所需的输出收音机"中,有一些缺失值.列manufacturer"、other_PN"中的值也包括在内.和part_number"必须跨多行复制.

This is the data frame I would like to get at the end. Note that in the desired output "radio" has some missing values. Also values in columns "manufacturer", "other_PN" and "part_number" have to be duplicated across several rows.

structure(list(type = c("radio", "radio", "television", "television", 
"television", "television", "television", "television", "television", 
"television", "television", "television"), Resource = c("samsung", 
"samsung", "samsung", "samsung", "samsung", "samsung", "samsung", 
"sony", "sony", "sony", "sony", "sony"), manufacturer = c("John", 
"John", "Walt", "Walt", "Walt", "Walt", "Walt", "John", "John", 
"John", "John", "John"), other_PN = c(NA, NA, "5g6h3f", "5g6h3f", 
"5g6h3f", "5g6h3f", "5g6h3f", "2a3b4c", "2a3b4c", "2a3b4c", "2a3b4c", 
"2a3b4c"), part_number = c(NA, NA, 6789, 6789, 6789, 6789, 6789, 
3461, 3461, 3461, 3461, 3461), lot_number = c(12345, 54321, 9876, 
12345, 54321, 56789, 67890, 9876, 12345, 54321, 56789, 67890)), class = c("spec_tbl_df", 
"tbl_df", "tbl", "data.frame"), row.names = c(NA, -12L), spec = structure(list(
    cols = list(type = structure(list(), class = c("collector_character", 
    "collector")), Resource = structure(list(), class = c("collector_character", 
    "collector")), manufacturer = structure(list(), class = c("collector_character", 
    "collector")), other_PN = structure(list(), class = c("collector_character", 
    "collector")), part_number = structure(list(), class = c("collector_double", 
    "collector")), lot_number = structure(list(), class = c("collector_double", 
    "collector"))), default = structure(list(), class = c("collector_guess", 
    "collector")), skip = 1), class = "col_spec"))

感谢您的帮助!!

推荐答案

我建议这种方法使用 dput() 数据作为 df.您可以使用 group_by() 创建一个 id 变量以识别行,然后您可以使用 pivot_wider() 进行整形.由于需要填充某些值,您可以使用 tidyr 中的 fill(),一个 tidyverse 包:

I would suggest this approach using your dput() data as df. You can create an id variable with group_by() in order to identify rows and then you can reshape with pivot_wider(). As some values need to be filled you can use fill() from tidyr, a tidyverse package:

library(tidyverse)
#Data
df %>% group_by(type,Resource,Property) %>% mutate(id=1:n()) %>%
  pivot_wider(names_from = Property,values_from=value) %>%
  fill(everything()) %>% select(-id)

输出:

# A tibble: 12 x 6
# Groups:   type, Resource [3]
   type       Resource lot_number manufacturer other_PN part_number
   <chr>      <chr>    <chr>      <chr>        <chr>    <chr>      
 1 radio      samsung  12345      John         NA       NA         
 2 radio      samsung  54321      John         NA       NA         
 3 television samsung  9876       Walt         5g6h3f   6789       
 4 television samsung  12345      Walt         5g6h3f   6789       
 5 television samsung  54321      Walt         5g6h3f   6789       
 6 television samsung  56789      Walt         5g6h3f   6789       
 7 television samsung  67890      Walt         5g6h3f   6789       
 8 television sony     9876       John         2a3b4c   3461       
 9 television sony     12345      John         2a3b4c   3461       
10 television sony     54321      John         2a3b4c   3461       
11 television sony     56789      John         2a3b4c   3461       
12 television sony     67890      John         2a3b4c   3461   

这篇关于如何pivot_wider 并通过复制值来填充缺失值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
相关文章
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆