使用 R，将多个卡方列联表检验应用于分组数据框，并添加一个包含检验 p 值的新列 [英] Using R, apply multiple chi-square contingency table tests to a grouped data frame and add a new column containing the p values of the tests

问题描述

我有一个类似于以下示例的数据框(这是我实际数据框的一小部分摘录).

I have a data frame similar to the example below (which is a small extract of my actual data frame).

frequencies <- data.frame(sex=c("female", "female", "male", "male", "female", "female", "male", "male", "female", "female", "male", "male", "female", "female", "male", "male"),
                      ecotype=c("Crab", "Wave", "Crab", "Wave", "Crab", "Wave", "Crab", "Wave", "Crab", "Wave", "Crab", "Wave", "Crab", "Wave", "Crab", "Wave"),
                      contig_ID=c("Contig100169_2367", "Contig100169_2367", "Contig100169_2367", "Contig100169_2367", "Contig100169_2367", "Contig100169_2367", "Contig100169_2367", "Contig100169_2367", 
                                  "Contig100169_2481", "Contig100169_2481", "Contig100169_2481", "Contig100169_2481", "Contig100169_2481", "Contig100169_2481", "Contig100169_2481", "Contig100169_2481"),
                      allele=c("p", "p", "p", "p", "q", "q", "q", "q", "p", "p", "p", "p", "q", "q", "q", "q"),
                      frequency=c(157, 98, 140, 65, 29, 8, 26, 9, 182, 108, 147, 80, 46, 4, 49, 4))

我想对contig_ID"和ecotype"的每个组合进行单独的卡方应变测试，测试性别"和等位基因"之间的关联.然后，我想在一个表中总结这些结果，其中包括contig_ID"和ecotype"的每个组合的 p 值.例如，从给出的示例表中，我希望得到一个包含 4 个 p 值的结果表，如下例所示.

I would like to do separate chi-square contingency tests for each combination of ‘contig_ID’ and ‘ecotype’, testing the association between ‘sex’ and ‘allele’. I would then like to summarise the results of these in a table that includes the p value for each combination of ‘contig_ID’ and ‘ecotype’. For instance, from the example table given, I would expect a results table of 4 p values like the example below.

results <- data.frame(ecotype=c("Crab", "Wave", "Crab", "Wave"),
                  contig_ID=c("Contig100169_2367", "Contig100169_2367", "Contig100169_2481", "Contig100169_2481"),
                  pvalue=c("pval", "pval", "pval", "pval"))

或者，只需在原始表中添加一个 p 值列也可以，每个组合的 p 值只是在所有相关行中重复.

Alternatively, just adding a p value column to the original table would also work, with the p value for each combination just repeated in all the relevant rows.

我一直在尝试使用 lapply() 和 summarise() 等函数结合 chisq.test() 来实现但是到目前为止还没有运气.我也尝试使用类似的方法:对表格中的每一行进行 R 卡方检验(3x2 列联表) ，但也无法完成这项工作.

I have been attempting to use functions such as lapply() and summarise() in combination with chisq.test() to achieve this but have had no luck so far. I have also attempted to use a method similar to this: R chi squared test (3x2 contingency table) for each row in a table , but couldn't make this work either.

推荐答案

我们可以将 contig_ID 和 ecotype 列分组并创建一个嵌套数据框，并将数据转换为矩阵如下.

We can group the contig_ID and ecotype columns and created a nested data frame with the data converted to a matrix as follows.

library(tidyverse)

frequencies2 <- frequencies %>%
  group_by(contig_ID, ecotype) %>%
  nest() %>%
  mutate(M = map(data, function(dat){
    dat2 <- dat %>% spread(sex, frequency)
    M <- as.matrix(dat2[, -1])
    row.names(M) <- dat2$allele
    return(M)
  }))

如果我们查看 M 列的第一个元素，我们会发现每个组的数据都被转换为矩阵.

If we look at the first element of the M column, we will find out that data from each group were converted to a matrix.

frequencies2$M[[1]]
#   female male
# p    157  140
# q     29   26

从这里，我们可以将 chisq.test 应用于每个矩阵并提取 p 值.frequencies3 是最终输出.

From here, we can applied the chisq.test to each matrix and pull out the p value. frequencies3 is the final output.

frequencies3 <- frequencies2 %>%
  mutate(pvalue = map_dbl(M, ~chisq.test(.x)$p.value)) %>%
  select(-data, -M) %>%
  ungroup()
frequencies3
# # A tibble: 4 x 3
#   contig_ID         ecotype pvalue
#   <fct>             <fct>    <dbl>
# 1 Contig100169_2367 Crab     1.00 
# 2 Contig100169_2367 Wave     0.434
# 3 Contig100169_2481 Crab     0.284
# 4 Contig100169_2481 Wave     0.958

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