如何解析 Python 中的自由文本时间间隔，范围从几年到几秒? [英] How can I parse free-text time intervals in Python, ranging from years to seconds?

问题描述

我想使用 Python 解析如下所示的自由文本时间间隔:

I would like to parse free-text time intervals like the following, using Python:

• 1 秒
• 2 分钟
• 3 小时
• 4 天
• 5 周
• 6 个月
• 7 年

有没有一种轻松的方法来做到这一点，最好是简单地调用一个库函数?

Is there a painless way to do this, ideally by simply calling a library function?

我试过了:

• dateutil.parser.parse()，它可以理解秒到小时，但不能理解为几天或更长时间.
• mx.DateTime.DateTimeDeltaFrom()，它可以理解几天但几周或更长时间失败，并且是静默的(例如，它可能会创建长度为 0 的间隔，或将2 个月"解析为2 分钟).

• dateutil.parser.parse(), which understands seconds through hours but not days or more.
• mx.DateTime.DateTimeDeltaFrom(), which understands through days but fails on weeks or higher, and silently (e.g., it might create an interval of length 0, or parse "2 months" as 2 minutes).

推荐答案

这个对我来说是新的，但是基于一些谷歌搜索，你是否尝试过 呜呜?

This one is new to me, but based on some googling have you tried whoosh?

还有 parsedatetime:

#!/usr/bin/env python
from datetime import datetime
import parsedatetime as pdt # $ pip install parsedatetime

cal = pdt.Calendar()
for time_str in ['1 second', '2 minutes','3 hours','5 weeks','6 months','7 years']:
    diff = cal.parseDT(time_str, sourceTime=datetime.min)[0] - datetime.min
    print("{time_str:<10} -> {diff!s:>20} <{diff!r}>".format(**vars()))

输出

1 second   ->              0:00:01 <datetime.timedelta(0, 1)>
2 minutes  ->              0:02:00 <datetime.timedelta(0, 120)>
3 hours    ->              3:00:00 <datetime.timedelta(0, 10800)>
5 weeks    ->     35 days, 0:00:00 <datetime.timedelta(35)>
6 months   ->    181 days, 0:00:00 <datetime.timedelta(181)>
7 years    ->   2556 days, 0:00:00 <datetime.timedelta(2556)>

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