日期时间:获取带有时区偏移量的时间戳 [英] datetime: get timestamp with timezone offset

问题描述

我想从以下格式的日期中获取时间戳:

I would like to get the timestamp from dates in the following formats:

Mon, 23 Nov 2020 19:00:00 GMT
Mon, 23 Nov 2020 20:00:00 +0100

我使用以下语句将日期转换为 datetime 对象:

I am using the the following statements to convert dates to datetime objects:

dateobj = datetime.datetime.strptime(date, '%a, %d %b %Y %H:%M:%S %Z')
dateobj = datetime.datetime.strptime(date, '%a, %d %b %Y %H:%M:%S %z')

但是使用 .timestamp() 方法，会打印与纪元不同的秒数.为什么 %Z 指令不向 datetime 对象添加时区信息?如何将时区考虑在内，使时间戳相等?

But using .timestamp() method, different seconds from epoch are printed. Why doesn't the %Z directive add timezone information to the datetime object? How could I get the timezone into account, so the timestamp is equal?

推荐答案

请注意 Python 中日期时间解析时区不一致.您的问题是 %Z，它使 strptime 接受 某些字符串(GMT、UTC 和 time.tzname 中的任何值 - docs)，但实际上并没有从中做出任何贡献.返回的日期时间对象是幼稚的——这就是为什么如果你调用它的 timestamp() 方法，Python 会假设它是本地时间.

Please note Inconsistent datetime parse timezone in Python. Your problem is %Z, it makes strptime accept certain strings (GMT, UTC and any value in time.tzname - docs), but doesn't actually make anything out of it. The returned datetime object is naive - which is why Python will assume it's local time if you call the timestamp() method of it.

您可以改用 dateutil 的解析器:

You can use dateutil's parser instead:

from dateutil.parser import parse

for s in ("Mon, 23 Nov 2020 19:00:00 GMT", "Mon, 23 Nov 2020 20:00:00 +0100"):
    dt = parse(s)
    print(repr(dt), dt.timestamp())

# datetime.datetime(2020, 11, 23, 19, 0, tzinfo=tzutc()) 1606158000.0
# datetime.datetime(2020, 11, 23, 20, 0, tzinfo=tzoffset(None, 3600)) 1606158000.0

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