如何编写符合条件使用PHP文本文件 [英] How to write a textfile with a condition using PHP
问题描述
我在code有问题。我的code是所有有关更新/被发现在删除灌胃文本文件文本文件的行。我有它的麻烦。起初,我可以添加一个新的文本文件,并与一起我也可以更新此文件。但它是对1行。如果我更新另一行。它只是在文本文件的末尾添加更新的值。我要的是更新这个或删除和插入新的。但我不知道怎么办。我在更新阵列过程array_replace()。首先,我需要找出如果我的数据的ID在文本文件中找到。如果找到了,我会简单的更新/删除和现有数据更换成我的新更新的数据。如果没有发现,只有只添加。
下面是我的code表示。
$ restaurant_id = $ post_data ['COMPANY_ID'];
$ new_lat_entry = $ post_data ['new_lat'];
$ new_long_entry = $ post_data ['new_long']; / ****这是我的新的更新阵列**** /
$ data_add =阵列(
restaurant_id'=> $ restaurant_id,
new_lat'=> $ new_lat_entry,
new_long'=> $ new_long_entry,
日期date_updated'=>日期('Y-M-D H:I:S')
);
/ ****这是从现有的文本文件的基本阵列**** /
$数据=反序列化(的file_get_contents('addresses.txt')); 目标$ = $ data_add ['restaurant_id']; 为($ I = 0; $ I<计数($的数据); $ I ++){ $ get_id = $数据[$ i] ['restaurant_id']; 如果($ get_id == $目标){ //如果找到ID - 更新 $ add_data工具=阵列(); $ add_data工具=阵列(
$ I => $ data_add
); $ new_array =阵列();
$ new_array = array_replace($数据,$ add_data工具); $ serialize_data =连载($ new_array);
$ file_input_txt =的fopen(addresses.txt,W +);
FWRITE($ file_input_txt,$ serialize_data);
FCLOSE($ file_input_txt); }其他{ $ new_array =阵列(
$ I => $ data_add
); $ serialize_data =连载($ new_array); $ file_input_txt =的fopen(addresses.txt,W +);
FWRITE($ file_input_txt,$ serialize_data);
FCLOSE($ file_input_txt);
} }
我的文本文件的输出是序列化的形式。
<$p$p><$c$c>a:1:{i:0;a:4:{s:13:\"restaurant_id\";s:4:\"1519\";s:7:\"new_lat\";s:8:\"14.63823\";s:8:\"new_long\";s:9:\"121.02999\";s:12:\"date_updated\";s:19:\"2013-11-15十二时42分59秒;}}这是所有球员请帮助我。我现在有一个最后期限。而且我坚持了下来。 :-(这是我第一次以一个文本文件,这就是为什么我有麻烦调试它创建一个CRUD。
能否请您试试这个,
&LT; PHP / ****这是从现有的文本文件的基本阵列**** /
$数据=反序列化(的file_get_contents('addresses.txt')); $ restaurant_id ='1519';
$ new_lat_entry = '14 0.64823';
$ new_long_entry ='121.45999'; / ****这是我的新的更新阵列**** /
$ data_add =阵列(
restaurant_id'=&GT; $ restaurant_id,
new_lat'=&GT; $ new_lat_entry,
new_long'=&GT; $ new_long_entry,
日期date_updated'=&GT;日期('Y-M-D H:I:S')
); 目标$ = $ data_add ['restaurant_id']; $计数=计数($的数据);
$ new_array =阵列();
为($ I = 0; $ I&LT; $计数; $ I ++){ $ get_id = $数据[$ i] ['restaurant_id'];
//如果找到ID - 更新 $ add_data工具=阵列(
$ I =&GT; $ data_add
); 如果($ get_id == $目标){
$ new_array = array_replace($数据,$ add_data工具);
} }
$ serialize_data =连载($ new_array); 的print_r($ serialize_data);
$ file_input_txt =的fopen(addresses.txt,W +);
FWRITE($ file_input_txt,$ serialize_data);
FCLOSE($ file_input_txt);
?&GT;
I have a problem in my code. My code is all about updating/deleting rows in textfile ig the textfile is found. I am having a trouble with it. At first I can add a new textfile and together with it I can also update this file. But it is for 1 row. If I update another row. It will just append the updated value at the end of the textfile. What I want is to update this or delete and insert the new one. But I don't know how. My process in updating the array is array_replace(). First I need to find out if the ID of my data is found in the textfile. If found I will simple update/delete and replace the existing data into my new updated data. If not found just add only.
Here's my code for that.
$restaurant_id = $post_data['company_id'];
$new_lat_entry = $post_data['new_lat'];
$new_long_entry = $post_data['new_long'];
/****Here's my new updated array ****/
$data_add = array(
'restaurant_id' => $restaurant_id,
'new_lat' => $new_lat_entry,
'new_long' => $new_long_entry,
'date_updated' => date('Y-m-d H:i:s')
);
/****This is the BASE array from the existing textfile ****/
$data = unserialize(file_get_contents('addresses.txt'));
$target = $data_add['restaurant_id'];
for ($i = 0; $i < count($data); $i++) {
$get_id = $data[$i]['restaurant_id'];
if($get_id == $target){
//If ID is found - UPDATE
$add_data = array();
$add_data = array(
$i => $data_add
);
$new_array = array();
$new_array = array_replace($data,$add_data);
$serialize_data = serialize($new_array);
$file_input_txt = fopen("addresses.txt","w+");
fwrite($file_input_txt,$serialize_data);
fclose($file_input_txt);
}else{
$new_array = array(
$i => $data_add
);
$serialize_data = serialize($new_array);
$file_input_txt = fopen("addresses.txt","w+");
fwrite($file_input_txt,$serialize_data);
fclose($file_input_txt);
}
}
The output of my text file is in serialized form.
a:1:{i:0;a:4:{s:13:"restaurant_id";s:4:"1519";s:7:"new_lat";s:8:"14.63823";s:8:"new_long";s:9:"121.02999";s:12:"date_updated";s:19:"2013-11-15 12:42:59";}}
That's all guys please help me. I have a deadline now. And I am stuck with it. :-( This is the first time I am creating a CRUD based on a text file that's why I am having a trouble debugging it.
Can you please try this,
<?php
/****This is the BASE array from the existing textfile ****/
$data = unserialize(file_get_contents('addresses.txt'));
$restaurant_id = '1519';
$new_lat_entry = '14.64823';
$new_long_entry = '121.45999';
/****Here's my new updated array ****/
$data_add = array(
'restaurant_id' => $restaurant_id,
'new_lat' => $new_lat_entry,
'new_long' => $new_long_entry,
'date_updated' => date('Y-m-d H:i:s')
);
$target = $data_add['restaurant_id'];
$Count =count($data);
$new_array =array();
for ($i = 0; $i < $Count; $i++) {
$get_id = $data[$i]['restaurant_id'];
//If ID is found - UPDATE
$add_data = array(
$i => $data_add
);
if($get_id == $target){
$new_array = array_replace($data,$add_data);
}
}
$serialize_data= serialize($new_array);
print_r($serialize_data);
$file_input_txt = fopen("addresses.txt","w+");
fwrite($file_input_txt, $serialize_data);
fclose($file_input_txt);
?>
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