如何将表示为字符串的二进制数拆分为子字符串 [英] How to split a binary number represented as a string to sub strings

问题描述

我正在处理一个二进制文件.并希望将一个二进制数拆分为更小的部分.

例如一个输入数字 01001100001011000100110000101100010011000 应该被解析为 0 1 00 11 0000 1 0 11 000 1 00 0 1 0 0 code 0 0 1 0 0 1 0/p>

这是我迄今为止尝试过的吗?

 from tkinter import filedialogfile_path = filedialog.askopenfilename()使用 open(file_path, 'rb') 作为 f:a = f.read打印(a.replaceint(01"，0 1"))打印(a.replaceint(10"，1 0"))打印(f，文件=打开(space.txt"，a"))

解决方案

这应该可行，如果您有任何问题，请告诉我.

import itertoolss = 01001100001011000100110000101100010011000"对于 itertools.groupby(s) 中的 k,v:打印(k*len(列表(v)))

I am working with a binary file. and want to split a binary number to smaller parts.

For example an input number 01001100001011000100110000101100010011000 should be parsed to 0 1 00 11 0000 1 0 11 000 1 00 11 0000 1 0 11 000 1 00 11 000.

This is what I have tried so far?

    from tkinter import filedialog
    
    file_path = filedialog.askopenfilename()
    
    with open(file_path, 'rb') as f:
        a = f.read
    
    print(a.replaceint("01", "0 1"))
    print(a.replaceint("10", "1 0"))
       
    print(f, file=open("space.txt", "a"))

解决方案

This should work, let me know if you have any questions.

import itertools

s = "01001100001011000100110000101100010011000"

for k,v in itertools.groupby(s):
    print(k*len(list(v)))

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