如何在命令行上传递 tomcat 端口号? [英] How to pass tomcat port number on command line?

问题描述

是否可以告诉 tomcat 使用特定端口而不是 server.xml 中指定的端口?或者在 server.xml 中将环境变量配置为端口号的方法?(我可以在启动 tomcat 的批处理文件中设置)

Is it possible to tell tomcat to use a particular port instead of the one specified in server.xml? Or a way to configure an environment variable as port number in server.xml? (which I can set in a batch file which starts tomcat)

本质上，我想启动一个 tomcat 实例的不同副本(版本)，而不必手动更改每个副本中的 server.xml，也不必记住哪个副本将在哪个端口启动.我希望在启动时指定端口号，以便在多个实例中不发生冲突.

Essentially, I want to launch different copies (versions) of a tomcat instance without having to manually change the server.xml in each of them and having to remember which one would launch at which port. I wish to specify the port number when I launch it so that there is no conflict in the multiple instances.

推荐答案

更改您的 server.xml，使其使用从属性扩展的端口号，而不是硬编码的端口号:

Change your server.xml so that it will use port numbers expanded from properties instead of hardcoded ones:

<Server port="${port.shutdown}" shutdown="SHUTDOWN">
...
  <Connector port="${port.http}" protocol="HTTP/1.1"/>
...
</Server>

以下是在 Linux 中启动的方法(假设您的当前目录是 CATALINA_HOME):

Here's how you can start in Linux (assuming your current directory is CATALINA_HOME):

JAVA_OPTS="-Dport.shutdown=8005 -Dport.http=8080" bin/startup.sh

在windows中应该是这样的:

In windows it should be smth like following:

set "JAVA_OPTS=-Dport.shutdown=8005 -Dport.http=8080"
bin\startup.bat

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