java.lang.IllegalArgumentException: Servlet 映射指定了一个未知的 servlet 名称 [英] java.lang.IllegalArgumentException: Servlet mapping specifies an unknown servlet name
本文介绍了java.lang.IllegalArgumentException: Servlet 映射指定了一个未知的 servlet 名称的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
当我尝试运行我的项目时出现错误
When I try run my project I get error
Caused by: java.lang.IllegalArgumentException: Servlet mapping specifies an unknown servlet name dispatcher
at org.apache.catalina.core.StandardContext.addServletMapping(StandardContext.java:3156)
at org.apache.catalina.core.StandardContext.addServletMapping(StandardContext.java:3135)
at org.apache.catalina.startup.ContextConfig.configureContext(ContextConfig.java:1372)
at org.apache.catalina.startup.ContextConfig.webConfig(ContextConfig.java:1176)
at org.apache.catalina.startup.ContextConfig.configureStart(ContextConfig.java:771)
at org.apache.catalina.startup.ContextConfig.lifecycleEvent(ContextConfig.java:305)
at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(LifecycleSupport.java:95)
at org.apache.catalina.util.LifecycleBase.fireLifecycleEvent(LifecycleBase.java:90)
at org.apache.catalina.core.StandardContext.startInternal(StandardContext.java:5154)
at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:150)
... 6 more
我的web.xml
:
<servlet>
<servlet-name>DispatcherServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
推荐答案
条目的
必须完全相同与
条目的
相同.
The <servlet-name>
of the <servlet-mapping>
entry must be exactly the same as the <servlet-name>
of the <servlet>
entry.
因此,在您的特定情况下,请更改
条目中的这一行
So, in your specific case, change this line in <servlet-mapping>
entry
<servlet-name>dispatcher</servlet-name>
到
<servlet-name>DispatcherServlet</servlet-name>
这篇关于java.lang.IllegalArgumentException: Servlet 映射指定了一个未知的 servlet 名称的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文