Python 翻译多个字符 [英] Python translate with multiple characters

问题描述

我正在尝试在 python 3.3.3 中创建一个程序，该程序将接受一个字符串，然后将其转换为数字 (1-26)

我知道如何处理一位数而不是 2 位

translist = str.maketrans("123456789", "ABCDEFGHI")

有没有办法做到这一点

解决方案

str.translate() 你不能为所欲为；仅适用于一对一替换.您正在尝试用两个不同的字符替换一个字符.

您可以改用正则表达式:

re.sub('[A-Z]', lambda m: str(ord(m.group()) - 64), inputstring)

这需要每个字母的 ASCII 代码点并减去 64(A 在 ASCII 标准中是 65).

请注意，这可能会导致一些令人困惑的模棱两可的解释:

<预><代码>>>>进口重新>>>inputstring = 'FOO BAR BAZ'>>>re.sub('[A-Z]', lambda m: str(ord(m.group()) - 64), inputstring)'61515 2118 2126'

第一组数字是 6 1 5 1 5 还是 6 15 15 ?您可能想要 0-pad 您的数字:

re.sub('[A-Z]', lambda m: format(ord(m.group()) - 64, '02d'), inputstring)

产生:

<预><代码>>>>re.sub('[A-Z]', lambda m: format(ord(m.group()) - 64, '02d'), inputstring)'061515 020118 020126'

I am trying to create a program in python 3.3.3 that will take a string then turn it into numbers (1-26)

I know how to do it for one digit but not 2

translist = str.maketrans("123456789", "ABCDEFGHI")

Is there a way to do this

解决方案

You cannot do what you want with str.translate(); that only works for one-on-one replacements. You are trying to replace one character with two different characters here.

You could use a regular expression instead:

re.sub('[A-Z]', lambda m: str(ord(m.group()) - 64), inputstring)

This takes the ASCII codepoint of each letter and subtracts 64 (A is 65 in the ASCII standard).

Note that this can lead to some confusing ambiguous interpretations:

>>> import re
>>> inputstring = 'FOO BAR BAZ'
>>> re.sub('[A-Z]', lambda m: str(ord(m.group()) - 64), inputstring)
'61515 2118 2126'

Is that 6 1 5 1 5 or 6 15 15 for the first set of numbers? You may want to 0-pad your digits:

re.sub('[A-Z]', lambda m: format(ord(m.group()) - 64, '02d'), inputstring)

which produces:

>>> re.sub('[A-Z]', lambda m: format(ord(m.group()) - 64, '02d'), inputstring)
'061515 020118 020126'

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