c#获取TreeView父节点列表 [英] c# Obtain a list of TreeView Parent nodes

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本文介绍了c#获取TreeView父节点列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如果我有一个 TreeView (myTreeview),我如何获得所有作为父节点的节点的列表?即有孩子的节点

If I have a TreeView (myTreeview),how can I obtain a list of all the nodes that are parent nodes? i.e. nodes that have children

推荐答案

myTreeview.Nodes 会给你一个由 MS 定义的根节点列表,基本上意味着树的根分支上的节点.

myTreeview.Nodes will give you a list of root nodes as defined by MS which basically means nodes on the root branch of the tree.

此代码将构建一个包含子节点的根节点列表:

This code will build a list of root nodes with children:

    IList<TreeNode> nodesWithChildren = new List<TreeNode>();
    foreach( TreeNode node in myTreeview.Nodes )
        if( node.Nodes.Count > 0 ) nodesWithChildren.Add( node );

<小时>

更新:如果您希望 TreeView 中的所有节点都有一个孩子,而不管树的深度如何,那么请使用一些递归,例如


Update: and if you wanted all nodes in the TreeView that had a child regardless of how deep into the tree then use a bit of recursion, e.g.

private static IList<TreeNode> BuildParentNodeList(TreeView treeView)
{
    IList<TreeNode> nodesWithChildren = new List<TreeNode>();

    foreach( TreeNode node in treeView.Nodes  )
        AddParentNodes(nodesWithChildren, node);

    return nodesWithChildren;
}

private static void AddParentNodes(IList<TreeNode> nodesWithChildren, TreeNode parentNode)
{
    if (parentNode.Nodes.Count > 0)
    {
        nodesWithChildren.Add( parentNode );
        foreach( TreeNode node in parentNode.Nodes )
            AddParentNodes( nodesWithChildren, node );
    }
}

<小时>

更新 2:只有 1 个 foreach 循环的递归方法:


Update 2: Recursion method with only 1 foreach loop:

private static IList<TreeNode> BuildParentNodeList(TreeView treeView)
{
    IList<TreeNode> nodesWithChildren = new List<TreeNode>();
    AddParentNodes( nodesWithChildren, treeView.Nodes );
    return nodesWithChildren;
}

private static void AddParentNodes(IList<TreeNode> nodesWithChildren, TreeNodeCollection parentNodes )
{
    foreach (TreeNode node in parentNodes)
    {
        if (node.Nodes.Count > 0)
        {
            nodesWithChildren.Add( node );
            AddParentNodes(nodesWithChildren, node.Nodes);
        }
    }
}

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