在字符串匹配上拆分字符串数据 [英] Split string data on a string match
问题描述
我正在处理一些 xml，我想在解析它之前清理它.我想具体做的是获取数据(下面的示例)并将其与字符串"匹配，然后在它离开节点之前修剪所有内容.然后我会匹配字符串 "</data>" 并截断它之后的所有内容，再次让匹配的节点保持原状.
I'm working with some xml and I'd like to clean it up before I parse it. What i'd like to do specifically, is take the data (example below) and match it on the string "<data>" and then trim everything before it leaving the node in tact. Then I would match on the string "</data>" and truncate everything after it, once again leaving the matched node in tact.
转这个:
<dwml>
<head>
<child></child>
</head>
<data>
<child></child>
<child></child>
</data>
<more></more>
</dwml>
进入这个:
<data>
<child></child>
<child></child>
</data>
我的问题:
虽然我确信有一种方法可以做到这一点，但我不知道从哪里开始.有人可以指出我正确的方向或更好的提供一个例子吗?感谢您的帮助.
My Question:
While I am sure there is a way to do this, I don't know where to start. Could someone could point me in the right direction or better yet provide an example? I appreciate any help.
推荐答案
您可以使用 componentsSeparatedByString 来隔离您的元素，如下所示:
You can use componentsSeparatedByString to isolate your elements as follow:
let xmlString = "<dwml><head><child></child></head><data><child></child><child></child></data><more></more></dwml>"
func filterData(input: String) -> String {
return "<data>" + input.componentsSeparatedByString("<data>").last!.componentsSeparatedByString("</data>").first! + "</data>"
}
filterData(xmlString) // "<data><child></child><child></child></data>"
您还可以使用 rangeOfString 来查找字符串的范围:
You can also use rangeOfString to find the range of your string:
func findData(input: String) -> String {
if let startIndex = input.rangeOfString("<data>", options: NSStringCompareOptions.LiteralSearch, range: nil, locale: nil)?.startIndex {
if let endIndex = input.rangeOfString("</data>", options: NSStringCompareOptions.LiteralSearch, range: nil, locale: nil)?.endIndex {
return input.substringWithRange(startIndex..<endIndex)
}
}
return ""
}
findData(xmlString) // "<data><child></child><child></child></data>"
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