真正的正则表达式在方括号中括号中的内容得到 [英] True regex for getting content from parentheses in square brackets

问题描述

我爱/恨，因为效用/硬度的正则表达式。 （我不知道为什么，但我不能构造格局:(）结果
我在我的数据库字段的一些记录这样的结果。

I love/hate the regex because of usefulness/hardness. (I don't why but I can't construct pattern :( )
I have some records in my database field like this

[（IP1 = 192.x 100？）（ID1 = 125485smds65）（日期1 = 11.02.2011-15：00 / 15.06.2012-17：30）（文本1 =写一些文字这可以包括所有括号和/或圆括号和放大器;任何字符等，像＆LT;？（文字}，[任意）{等**）] [（IP2 = xx20）（NUM2 = 1235845）（文本2 =许多话：））] ... 搜索

好吧，我想返回包含值作为一个数组;结果

Ok, I want to return an array that contain value as;

$result[ip1] = 192.x.?.100;
$result[id1] = 125485smds65;
$result[date1] = 11.02.2011-15:00/15.06.2012-17:30;
$result[text1] = Some text that can include all brackets and/or parentheses & any chars etc, like < ( text . } , [ any ) ] { etc.**;
$result[ip2] = 192.x.?.100;
$result[num2] = 1235845;
$result[text2] = many other words :)

您可以看到的是，在括号和括号数量的数据数量可能会有所不同。

You can see that, number of data in the brackets and brackets number can vary

那么，什么是preg_match_all正则表达式的真正模式来收集上述数据？

So, what is the true pattern for preg_match_all regex to collect above data?

推荐答案

尝试是这样的：

$s = '(ip1=192.x.?.100)(id1=125485smds65)(date1=11.02.2011-15:00/15.06.2012-17:30)
(text1=Some text that can include all brackets and/or paranthesis & any chars etc, 
like < ( text . } , [ any ) ] { etc.**)][(ip2=x.x.20.?)(num2=1235845)
(text2=many other words :))';

preg_match_all('/\((?:[^()]|(?R))*\)/', $s, $matches);

print_r($matches);

这将打印：

Array
(
    [0] => Array
        (
            [0] => (ip1=192.x.?.100)
            [1] => (id1=125485smds65)
            [2] => (date1=11.02.2011-15:00/15.06.2012-17:30)
            [3] => (text1=Some text that can include all brackets and/or paranthesis & any chars etc, 
like < ( text . } , [ any ) ] { etc.**)
            [4] => (ip2=x.x.20.?)
            [5] => (num2=1235845)
            [6] => (text2=many other words :)
        )

)

的（？R）中的正则表达式 / \\（（？：？[^（）] |（R））* \\ ）/ 是整个模式iteself递归调用。

The (?R) in the regex pattern /\((?:[^()]|(?R))*\)/ is the recursive call to the entire pattern iteself.

由于是从你的问题下面的意见明确：它不建议在生产中使用code这样的正则表达式，巫术。我的建议是你的不的存储就像你在你的数据库的方式做你的数据。解决这一问题的根源，请！

As is clear from the comments beneath your question: it is not recommended to use such regex-voodoo in production code. My suggestion is you not store your data like the way you do in your database. Solve the issue at the root, please!

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