解包元组的pythonic方法是什么? [英] What is the pythonic way to unpack tuples?

问题描述

这太丑了.什么是更 Pythonic 的方式来做到这一点?

导入日期时间t= (2010, 10, 2, 11, 4, 0, 2, 41, 0)dt = datetime.datetime(t[0], t[1], t[2], t[3], t[4], t[5], t[6])

解决方案

通常，您可以使用 func(*tuple) 语法.您甚至可以传递元组的一部分，这似乎是您在此处尝试执行的操作:

t = (2010, 10, 2, 11, 4, 0, 2, 41, 0)dt = datetime.datetime(*t[0:7])

这称为解包元组，也可用于其他可迭代对象(例如列表).这是另一个示例(来自 Python 教程):

<预><代码>>>>range(3, 6) # 带有单独参数的普通调用[3, 4, 5]>>>参数 = [3, 6]>>>range(*args) # 使用从列表中解压出来的参数调用[3, 4, 5]

This is ugly. What's a more Pythonic way to do it?

import datetime

t= (2010, 10, 2, 11, 4, 0, 2, 41, 0)
dt = datetime.datetime(t[0], t[1], t[2], t[3], t[4], t[5], t[6])

解决方案

Generally, you can use the func(*tuple) syntax. You can even pass a part of the tuple, which seems like what you're trying to do here:

t = (2010, 10, 2, 11, 4, 0, 2, 41, 0)
dt = datetime.datetime(*t[0:7])

This is called unpacking a tuple, and can be used for other iterables (such as lists) too. Here's another example (from the Python tutorial):

>>> range(3, 6)             # normal call with separate arguments
[3, 4, 5]
>>> args = [3, 6]
>>> range(*args)            # call with arguments unpacked from a list
[3, 4, 5]

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