在python的一行中读取两个单独的值 [英] Reading two separate values in one line in python

问题描述

我需要你的帮助.到目前为止，这是我的程序

I need your help. This is my program so far

import turtle
turtle.showturtle()

def turtle_interface():
    while True :
          n = 0
          instructions = input().split()
          i = instructions[0]
          if len(instructions) > 1:
              n = int(instructions[1])
              if i == 'forward' :
                  turtle.forward(n)
              elif i == 'backward' :
                  turtle.backward(n)
              elif i == 'left' :
                  turtle.left(n)
              elif i == 'right' :
                  turtle.right(n)
              elif i == 'quit' :
                  break
              elif i == 'new' :
                  turtle.reset()
              else :
                  continue

print('Control the turtle!')
turtle_interface()

如您所见，当字符串后面没有 [n] 时，它将被忽略.我该如何解决这个问题?

As you can see, when the string has no [n] after it, it's being ignored. How can I fix this?

推荐答案

我认为是因为 if len(instructions) >1: 测试.如果字符串后面没有[n]，那么就只有一条指令，长度不会大于1.

I think it is because of the if len(instructions) > 1: test. If the string has no [n] after it, then there will only be one instruction, and the length will not be greater than 1.

你应该尝试这样的事情:

You should try something like this:

def turtle_interface():
    while True :
          n = 0
          instructions = input().split()
          i = instructions[0]
          if len(instructions) > 1:
              n = int(instructions[1])
              if i == 'forward' :
                  turtle.forward(n)
              elif i == 'backward' :
                  turtle.backward(n)
              elif i == 'left' :
                  turtle.left(n)
              elif i == 'right' :
                  turtle.right(n)
          elif i == 'new' :
              turtle.reset()
          elif i == 'quit' :
              break

注意 if i == 'new' 行的缩进和位置.

Note the indentation and placement of the line for if i == 'new'.

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