Django Tweepy 无法访问 Amazon S3 文件 [英] Django Tweepy can't access Amazon S3 file

问题描述

我正在使用 Tweepy，一个推文 Python 库，django-storages 和 boto.我有一个自定义的 manage.py 命令，它可以在本地正常工作，它从文件系统中获取一个图像并将该图像发送到推文中.但是，如果我将存储更改为 Amazon S3，则无法访问该文件.它给了我这个错误:

I'm using Tweepy, a tweeting python library, django-storages and boto. I have a custom manage.py command that works correctly locally, it gets an image from the filesystem and tweets that image. If I change the storage to Amazon S3, however, I can't access the file. It gives me this error:

 raise TweepError('Unable to access file: %s' % e.strerror)

我尝试将存储桶中的图像设为公开".没用.这是代码(它在没有 S3 的情况下工作):

I tried making the images in the bucket "public". Didn't work. This is the code (it works without S3):

filename = model_object.image.file.url
media_ids = api.media_upload(filename=filename)  # ERROR

params = {'status': tweet_text, 'media_ids': [media_ids.media_id_string]}
api.update_status(**params)

这一行:

model_object.image.file.url

给我我想要推特的图片的完整网址，如下所示:

Gives me the complete url of the image I want to tweet, something like this:

https://criptolibertad.s3.amazonaws.com/OrillaLibertaria/195.jpg?Signature=xxxExpires=1467645897&AWSAccessKeyId=yyy

我也尝试手动构建 url，因为它是存储在我的存储桶中的公共图像，如下所示:

I also tried constructing the url manually, since it is a public image stored in my bucket, like this:

filename = "https://criptolibertad.s3.amazonaws.com/OrillaLibertaria/195.jpg"

但它不起作用.

¿为什么我会收到无法访问文件错误?

¿Why do I get the Unable to access file error?

来自 tweepy 的源代码如下所示:

The source code from tweepy looks like this:

def media_upload(self, filename, *args, **kwargs):
    """ :reference: https://dev.twitter.com/rest/reference/post/media/upload
        :allowed_param:
    """
    f = kwargs.pop('file', None)
    headers, post_data = API._pack_image(filename, 3072, form_field='media', f=f)  # ERROR
    kwargs.update({'headers': headers, 'post_data': post_data})


def _pack_image(filename, max_size, form_field="image", f=None):
        """Pack image from file into multipart-formdata post body"""
        # image must be less than 700kb in size
        if f is None:
            try:
                if os.path.getsize(filename) > (max_size * 1024):
                    raise TweepError('File is too big, must be less than %skb.' % max_size)
            except os.error as e:
                raise TweepError('Unable to access file: %s' % e.strerror)

看起来 Tweepy 无法从 Amazon S3 存储桶中获取图像，但我该如何使其工作?任何建议都会有所帮助.

Looks like Tweepy can't get the image from the Amazon S3 bucket, but how can I make it work? Any advice will help.

推荐答案

当 tweepy 尝试在 _pack_image 中获取文件大小时出现问题:

The issue occurs when tweepy attempts to get file size in _pack_image:

if os.path.getsize(filename) > (max_size * 1024):

函数os.path.getsize 假定它在磁盘上有一个文件路径；但是，在您的情况下，它会给出一个 URL.自然地，在磁盘上找不到该文件并引发 os.error.例如:

The function os.path.getsize assumes it is given a file path on disk; however, in your case it is given a URL. Naturally, the file is not found on disk and os.error is raised. For example:

# The following raises OSError on my machine
os.path.getsize('https://criptolibertad.s3.amazonaws.com/OrillaLibertaria/195.jpg')

你可以做的是获取文件内容，暂时保存到本地，然后发推:

What you could do is to fetch the file content, temporarily save it locally and then tweet it:

import tempfile


with tempfile.NamedTemporaryFile(delete=True) as f:
    name = model_object.image.file.name
    f.write(model_object.image.read())
    media_ids = api.media_upload(filename=name, f=f)
    params = dict(status='test media', media_ids=[media_ids.media_id_string])
    api.update_status(**params)

为了您的方便，我在这里发布了一个完整的示例:https://github.com/izzysoftware/so38134984

For your convenience, I published a fully working example here: https://github.com/izzysoftware/so38134984

这篇关于Django Tweepy 无法访问 Amazon S3 文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！